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# 1  
Old 08-31-2006
unix

Hi friends,

I have on data file containing 3 coloums...........

like this.


**** ***** *****
*** ***** *****
*** ***** *****
12.36 13,27 22.16
**** ***** *****
**** ***** *****
**** ***** *****
**** ***** *****
12.35 32.46 34.56

now from the above file i want to write only where the 3 fields are not blank.

can i use awk command.......
plz give me sysntax/........
# 2  
Old 08-31-2006
empty lines?

Do you mean to say the lines are empty..Then just delete the lines
Code:
sed '/^[ \t]*$/d' inputfile

or
Code:
sed '/^$/d' inputfile

# 3  
Old 08-31-2006
the above command not working.....
do u know awk syntax.............
i want only which row has the data based on third coloum..
# 4  
Old 08-31-2006
does this work

Code:
awk 'NF==3' inputfile

# 5  
Old 09-01-2006
thank u for reply.................
it not working......

actually my question is display the lines where field 3 is not blank.

so the output should like this....

23.12 78.34 22.1
17.68 65.34 24.5
21.78 70.87 26.8

please verify and let me know............


thank u
rajan
# 6  
Old 09-01-2006
Try...
Code:
awk '$3+0!=0' file1

Or...
Code:
awk '$3!~/^*+$/' file1

# 7  
Old 09-01-2006
So you don't want the "***" fields? only everything else? yes/no?
ie
grep -v "^*" filename
23.12 78.34 22.1
17.68 65.34 24.5
21.78 70.87 26.8
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