Shell Programming and Scripting

what is command for getting a list of file in the particular folder.

Assume X is folder where y is subfolder inside X and there is one file called abc.text.

While giving this command it would return two value ie abc.txt and y.

Code:

$cd X
$ls -lrt *.txt |cut -c55-120

I am only looking the value of abc.txt not X

Can anyone please advice what is best to capture only abc.txt.

also how this can be set into a varibale v_file in unix script.

is this correct

Code:

v_file=`echo ls -lrt *.txt |cut -c55-120'

thanks in advance

Try
ls -tlr | grep -v "^d"

This will remove the direcories in the output of ls -ltr.


regards
Apoorva Kumar

It isn't very clear what you want, dude. You do a 'cd X', and then run 'ls -rlt *.txt', then in your example, the only output that will be thrown is the abc.txt file. The directory X will never come up at all...

Would be better to just know what you want to do (you want to get the names of all .txt files inside the directory or something like that).

dude,

I am trying to get the filename by putting a command and then I want to use this in variable to write in some other file.

echo ls -lrt *.txt | grep -v "^d"|cut -c55-120'

but it gives me a no such file or directory, but simply giving the above command is returning one value.

could you tell me why ...is something wrong in the command?

If you just want to get a list of filenames, then why make things so complicated?

Do you just want the *.txt files? Then use something like this:

Code:

cd X
for file in *.txt; do
   #do whatever that you want with the file here
done