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quoting in conditional statement

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# 1  
Old 08-13-2006
quoting in conditional statement
can somebody help, what quote i should use in below statement or what wrong of it ?
the 1st (*) is a char, the 2nd and 3rd (*) is a wildcard


if [[ "$a" = * -o "$a" = *$c* ]] && [[ $d = abc -o $e = xyz ]] && [.....]]
................^ .............^
then
echo "ok"
fi

thanks in advance.
# 2  
Old 08-13-2006
Try:

Code:
if [[ "$a" = * || "$a" = *$c* ]] && [[ $d = abc || $e = xyz ]] && [.....]]

# 3  
Old 08-14-2006
Within [[ ]] tests, the = operator test for a pattern.
If you want to use * as a simple char, put it between quotes or escape it.

Code:
if [[ "$a" = '*' || "$a" = *$c* ]]

or

if [[ "$a" = \* || "$a" = *$c* ]]


Jean-Pierre.
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