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Accessing invidual characters in a variable name

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# 1  
Old 07-31-2006
Accessing invidual characters in a variable name
hi,

How do i access individual characters in a string variable value .
say i have var=20060731.
How do i retrieve 2,0,0,6 etc chars separately.
Is there any Field separator in cut or awk to achieve the same?

Regards,
Suman
# 2  
Old 07-31-2006
I got the answer.
Using cut -c option i can print what ever the bytes i am intrested in.

Thanks.
# 3  
Old 07-31-2006
Using awk:

Code:
$ var=20060731
$ echo $var | awk -F'@' '{print substr($1,1,1)}'
2
$ echo $var | awk -F'@' '{print substr($1,2,1)}'
0
$ echo $var | awk -F'@' '{print substr($1,3,1)}'
0
$ echo $var | awk -F'@' '{print substr($1,4,1)}'
6
$

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