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Awk an file size

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# 1  
Old 07-24-2006
Awk an file size
I have been using
Code:
x=ls -la "$f" | awk '{print $5}'

This allows me to the size of all the files in $f and echo $x later .

The only problem is instead of protecting the file size format of ls -la which is right to left, it rearranges it and reads it left to right.


Cyborg was kind enough to point out this command however and it works on the command line.
Code:
ls -la | awk '{len = length($5) > len ? length($5) : len ; arr[NR] = $5 }END{ for ( a = 1; a < NR; a++ ) { printf "%"len"s\n" , arr[a]}}'

When i try to modify it like this
Code:
x=ls -la  "$F" | awk '{len = length($5) > len ? length($5) : len ; arr[NR] = $5 }END{ for ( a = 1; a < NR; a++ ) { printf "%"len"s\n" , arr[a]}}'

It does not work. Can anyone give me any ideas?

Chris
# 2  
Old 07-24-2006
If someone has already answered your query, then why you started a new thread? You should have posted in the same thread. Try this:
Code:
x=`ls -la  "$F" | awk '{len = length($5) > len ? length($5) : len ; arr[NR] = $5 }END{ for ( a = 1; a <= NR; a++ ) { printf "%"len"s\n" , arr[a]}}'`

Regards,
Tayyab
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