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$line command problem

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# 1  
Old 07-21-2006
$line command problem
Hi all!

I have a problem with line command. The aim is to write each line of stdin into a text file.

For example with this command:

Code:
$find /
/usr/share/zoneinfo/WET
/usr/share/zoneinfo/Zulu
/usr/share/zoneinfo/iso3166.tab
/usr/share/zoneinfo/localtime
/usr/share/zoneinfo/zone.tab
/usr/src
/initrd.img
/vmlinuz

I want to write in a file the always the last line printed to stdin, to real-time follow proces execution.

I tried this:

Code:
$find / | line > stdout.file       (no results, only write the first line and exit)
$find / | tail -f -n 1 > stdout.file       (no results, only write the last line and exit)


Any ideas?
Thank you very much
# 2  
Old 07-21-2006
Can you re state your problem. First you are saying that you want to print each line then you are saying only last line...
# 3  
Old 07-21-2006
Try something like this :

Code:
find / |
while read line
   echo $line > stdout.file
done

The stdout.file will allways contains the last line printed by find on stdout

Jean-Pierre.
# 4  
Old 07-21-2006
Thank you Jean-Pierre, the correct code that works is:

Code:
find / |
while read line ; do
   echo $line > stdout.file
done

Thank you very much!
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