Shell Programming and Scripting

I have 20 files in a direcotry like BARE01_DLY_MKT_YYYYMMDD. The MKT differes for all these files but the remaining syntax remains the same for a particular day. If I am checking for today I need to make sure that there are 20 files that start with BARE01_DLY_MKT_20060720. How can I write a shell script to do this? I think I have to use for loop but don't know how to check for today or not. Kindly help.

Using ksh:

Code:

integer filecount=0
for file in BARE01_DLY_???_$(date +%Y%m%d); do
  filecount=$filecount+1
done
echo $filecount

Your test could look something like:

Code:

if (( $filecount == 20 )); then
  print "True"
else
  print "False"
fi

You can also do something like this :

Code:

integer filecount=$(ls BARE01_DLY_???_$(date +%Y%m%d) 2>/dev/null | wc -l)

Jean-Pierre.

Pierre,

Do you mean i have to have the code like this:

integer filecount=0
for file in BARE01_DLY_???_$(date +%Y%m%d); do
filecount=$filecount+1
done
echo $filecount

if (( $filecount == 20 )); then
print "True"
else
print "False"
fi

is this right? How can i embed them in the single KSH script. Please let me know.

I don't know what you expect as output. Without knowing all your requirements (and without having a desire to write the entire script for you), I would do:

check20.sh:

Code:

#!/bin/ksh
integer filecount=0
for file in BARE01_DLY_???_$(date +%Y%m%d); do
  filecount=$filecount+1
done

if (( $filecount == 20 )); then
  exit 0 # exit with success
else
  exit 1 # exit with failure
fi

Glenn,

I am sorry if I had asked to mean to write a script. But I created the script with the statements. What I need to know is I need to pass the name of the file as a parameter to the script and then do the processing we had before. How can this be possible.

The name of the files will look like BARE01_DLY_MKT_yyyymmdd for 20 markets. This script need to work for files named BARE02_DLY_MKT_20060803
which will be 20 again. So I need to generalise the script and pass the name of the file as parameter. So how can acheive this. Please let me know. I am trying to learn and develop at the same time.

Once again I appreicate your knid response.

Glenn,

Thank you very much it's throughing an error now. But if I don't need to pass the whole name of the file but just BARE01_DLY.

some thing like this: check20.sh BARE01_DLY

But it has to check whether 20 files are present for that day or not? I am using the code below. It's not working. What's wrong in this?

#!/bin/ksh
myfilepattern=$@
integer filecount=0
for file in $myfilepattern_$(date +%Y%m%d); do
filecount=$filecount+1
done

if (( $filecount == 20 )); then
exit 0
else
exit 1
fi

Please suggest