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awk compound statements

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# 1  
Old 07-13-2006
Error awk compound statements
how can i use two or multiple statements in the if part
of an awk code

for example
i want to check two flag if they are true i will write some print
operations and increase the counter.
here is the c version of the code that i want to write:

counter=0;
if (flag1==1 && flag2==0) {
printf("true\n");
counter=counter+1;
flag1=0;
}
else
printf("false");


how can i do the same operation using awk?
# 2  
Old 07-13-2006
just like you said.......
# 3  
Old 07-14-2006
Error
i dont think that, its just like i said.
(at least i couldnt make it work)

let me ask my question with a different example.
i wrote an awk code as follows,
and i cannot make it work, my guess is: the problem stems from
the compund statements. whats wrong with this code?

for file in TESTFILE*; do
counter1=0;
counter2=0;
awk -F" " '{ if ( $1 = /flag1/ ) { print "TRUE"; $2="true"; counter1=$counter1+1}
else { print "FALSE"; counter2=$counter2+1 }}' $file>testfileoutput
done
print $counter1
print $counter2
# 4  
Old 07-14-2006
Awk tests in the form

Code:
$1 == "foo" && $2 == "bar"

are perfectly acceptable, as is
Code:
$1 ~ /^foo$/ && $2 ~ /^bar$/

Check out http://www.vectorsite.net/tsawk2.html#m3. That should help you.
# 5  
Old 07-14-2006
Quote:
Originally Posted by gfhgfnhhn
i dont think that, its just like i said.
(at least i couldnt make it work)

let me ask my question with a different example.
i wrote an awk code as follows,
and i cannot make it work, my guess is: the problem stems from
the compund statements. whats wrong with this code?

for file in TESTFILE*; do
counter1=0;
counter2=0;
awk -F" " '{ if ( $1 = /flag1/ ) { print "TRUE"; $2="true"; counter1=$counter1+1}
else { print "FALSE"; counter2=$counter2+1 }}' $file>testfileoutput
done
print $counter1
print $counter2
if you're hoping to see SHELL vars being incremented and exported from 'awk' and being seen in SHEEL after the end of the loop... that is NOT how it works.

Also your increment [counter1=$counter1+1] withIN the awk is NOT what you THINK it's supposed to do.

Code:
#!/bin/ksh
for file in TESTFILE*; do
    counter1=0;
    counter2=0;
    eval $(nawk -v out='testfileoutput -v counter1="${counter1}" -v counter2="${counter2}" '{ 
          if ( $1 = /flag1/ ) { 
             print "TRUE" > out 
             $2="true";
             counter1++
          }
          else {
             print "FALSE" > out
             counter2++
          }
     }
     END {
         printf("export counter1=%d\nexport counter2=%d\n", counter1, counter2)
     }' $file )
done
print $counter1
print $counter2

Last edited by vgersh99; 07-14-2006 at 01:02 PM..
# 6  
Old 07-15-2006
Quote:
Originally Posted by vgersh99
if you're hoping to see SHELL vars being incremented and exported from 'awk' and being seen in SHEEL after the end of the loop... that is NOT how it works.

Also your increment [counter1=$counter1+1] withIN the awk is NOT what you THINK it's supposed to do.

Code:
#!/bin/ksh
for file in TESTFILE*; do
    counter1=0;
    counter2=0;
    eval $(nawk -v out='testfileoutput -v counter1="${counter1}" -v counter2="${counter2}" '{ 
          if ( $1 = /flag1/ ) {

Perhaps $1 ~ /flag1/.
Quote:
Code:
             print "TRUE" > out 
             $2="true";

After this assignment, is $2 or $0 ever used?
Quote:
Code:
             counter1++
          }
          else {
             print "FALSE" > out
             counter2++
          }
     }
     END {
         printf("export counter1=%d\nexport counter2=%d\n", counter1, counter2)
     }' $file )
done
print $counter1
print $counter2

# 7  
Old 07-17-2006
Error
thanks for your replies
but there is one more thing that i want to ask

eval $(nawk -v out='testfileoutput -v counter1="${counter1}" -v counter2="${counter2}" '

why i cannot use the above line as follows:

eval $(nawk '-v out=testfileoutput -v counter1="${counter1}" -v counter2="${counter2}" '


i moved the first single quote to just after nawk, before -v
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