Shell Programming and Scripting

Hello All,

I am trying to write a KSH script that would extract lines from a logfile, within a certain timeframe, in reverse order.

Ex.
-Sample logfile-
INFO 2006-07-12 00:23:00 - ModeDecision Time in WF:27
INFO 2006-07-12 00:24:00 - NRT_MQ_RES:108
INFO 2006-07-12 00:25:00 - getRecords() :R4000 :37
INFO 2006-07-12 00:26:00 - ModeDecision Time in WF:43
INFO 2006-07-12 00:27:00 - JDBC [PADRECORD] : 5

From the sample logfile above, I am needing to extract the lines starting from '00:27:00' to three minutes prior (00:24:00). I could not find anything from the 'date' command that would reverse time.

Any help would be greatly appreciated!

Code:

grep '^INFO 2006-07-12 00:' logfile | grep -e ':24:' -e ':25:' -e ':27:00' | sort -r

Thank you Jim!!! This syntax works beautifully and it's exactly what I needed!!!!!!

Thanks again!!