Shell Programming and Scripting

Here, you are storing the exit status of `TZ=EDT+24 date +%m%d%y` into retcode variable. Looking at what you do with it below, makes me think this is a mistake. I would remove that line from there.

I would also change:
into:

Code:

if [[ "$(ps -e | grep script1.ksh | grep -v grep)" = "" ]]

Here, is where you are echoing the exit status of `TZ=EDT+24 date +%m%d%y` and I suppose that what you want is the exit status of script2.ksh. In this case I would give execution perms to script2, and add the line

Code:

#!/bin/ksh -x

at the begining of script1 and script2
(Notice there are no spaces in "#!/bin/ksh" until the "-x" parameter)

Then, I would call the script like this;

Code:

/path/to/script2.ksh >> $BBLOG/$datestamp.log 2 >&1
retcode=$?
echo $retcode

Well, call script1 like this:

Code:

/path/to/script1 > script1.log 2>&1

This should work.

Hope this help.

Regards.

Thanks a zilliion grial!

All your suggestions really worked but the last one...

when i try to execute script1.ksh > script1.log 2 >&1
i see all the log again on the terminal rather than in the file to store.

so I tried . script1.ksh and now i'm able to create the log.

Anywayz, one clarification still remaining..can u pls throw light on what is returned by

"ps -e | grep script2 | grep -v grep " ?

Way to go!

It detects whether script2 is running or not.

that much for ps -e | grep script2..

what is grep -v grep in the expression for?

TY!

Sometimes, grep command is also displayed when you execute a "ps -ef | grep something". "-v" option means "everything but". For instance:

Code:

$ ps -ef | grep bash
root 26788 25538   0 13:54:58  pts/2  0:00 grep bash

As you can see, there are no bash running but the command above displays a "grep bash" which is a "false positive"
Regards.

OOF.. All questions patiently answered!

Thank you very much... grial, thestevew and vino!