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getting the most recent file

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# 1  
Old 06-22-2006
getting the most recent file
Hi,
I have files coming in every day with that days timestamp like:
nameyyyymmddhhmmss.ext.
I need the most recent one and so i am using

cat `ls -t name*|head -1 ` > temp

i am sorting the files in the decending order and am copying the most recent one into a temp file.
It works at times but sometimes it does not.
Is there a better way to do it?
I dont want to compare it to todays absolute date ;I just want the most recent file.
any suggestions will be appreciated.
thanks
# 2  
Old 06-22-2006
Code:
ls -1 * | sed 's/^[^0-9][^0-9]*\([0-9][0-9]*\).*/\1 &/' | sort -n | cut -d ' ' -f2- | tail -1

Last edited by vgersh99; 06-22-2006 at 04:03 PM..
# 3  
Old 06-22-2006
Can you explain the
[^0-9]*\([0-9][0-9]*\).*/\1 &/'
part?
thanks
# 4  
Old 06-22-2006
Quote:
Originally Posted by anujairaj
Can you explain the
[^0-9]*\([0-9][0-9]*\).*/\1 &/'
part?
thanks
1. anything BUT the numberS followed by
2. any number of digits followed by
3 anything

output 'bullet item '2' followed by ' ' and followed by the entire string
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