When comparing binary files, show human readable result?
Hello.
I am comparing two binary file.
The first file is the source file. The second file is a modified version of the first one.
Modification concern uuid value.
Example
first file have multiple occurrences of 69a3604b-ac2b-43b7-af84-0a4a67fc6962 second file have the same occurence number with "e1accb44-ce59-40a4-9a85-0905c05cdc86"
I want to verify that the only difference between the file are 69a3604b-ac2b-43b7-af84-0a4a67fc6962 replaced by e1accb44-ce59-40a4-9a85-0905c05cdc86
Using a tip found on internet, What i am able to do is to print an address offset, the value for the first file and the value for the second file.
Something like :
followed by the next occurence
I would like to have something like
or
Any help is welcome
Scripting Language: bash shell script, python
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1394553600,"test","79799776.0","19073982.728571","77547576.0","18835699.285714"
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find "$inputDirectory" \( -name 'very long pattern1'
-o -name 'very long pattern2'
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I want to list all the directories present in a particular location and want to display their sizes as well. I know "ls -lh" but it doesn't show the size of the complete directory. So i want something like
dir1 266 MB
dir2 2 KB
dir3 22 MB
...
...
file1 10 Kb
.....
Thanks
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$ quota
Disk quotas for user cqlouis (uid 1254):
Filesystem blocks quota limit grace files quota limit grace
/dev/sdb1 64 300000 320000 8 0 0
$
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This is what I have to start out with
more file
1208217600
1208131200
1193806800
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Hi,
The following command provides the usage in 1024-byte blocks
du -ks * | sort -n | echo "$1"
...
1588820 user10
2463140 user11
2464096 user12
5808484 user13
6387400 user14
.....
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