awk IF date comparison help


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# 8  
In awk, the rand() function is seeded with the actual system epoch time, and srand() "returns the value of the previous seed" (c.f. man awk). No need to supply an external datetimestamp. Try this



Code:
aws storagegateway describe-tape-archives | awk 'BEGIN { DT = srand() - 86400 * 90}; $5 < DT'

# 9  
Hello, back at this again


So I know this tape is older than 90 days, the 2nd and 5th colum (archive and creation date) are both past 90 days.



TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776


I tried running aws storagegateway describe-tape-archives | awk 'BEGIN { DT = srand() - 86400 * 90}; $5 < DT'


and it's doesn't return any tapes. I think the issue that I'm having is that the epoch dates in the 2nd and 5th column are in a string and I need to get it converted to a int to compare?
# 10  
Well, for me that line IS returned, be it $2 or $5 that are considered:
Code:
cat file | awk 'BEGIN { DT = srand() - 86400 * 90}; $5 < DT' 
TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776

, as both dates are more than 90 days past:
Code:
$ date -d@1572970010.744
Di 5. Nov 17:06:50 CET 2019
$ date -d@1572283447.819
 Mo 28. Okt 18:24:07 CET 2019


Sure that line is the output of aws storagegateway describe-tape-archives?
# 11  
I reran the command and I'm still unable to get the line to output. For testing, i created a test file that had just that line in it, and piped it into the awk command, and I'm still unable to get it to show up.

Code:
kruz@ces-lt-it-kg:~$ cat test
TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776
kruz@ces-lt-it-kg:~$ cat test | awk 'BEGIN { DT = srand() - 86400 * 90}; $5 < DT'
kruz@ces-lt-it-kg:~$


I am running these commands on the Windows Subsystem for Linux if that would make a difference? Maybe I have a different awk version that's behaving differently?
# 12  
Here:

Code:
cat file
TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776
cat file | awk 'BEGIN { DT = srand() - 86400 * 90}; $5 < DT'
TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776


You might want to develop some creativity when it comes to debugging your scripts / programs. What would be the output of
Code:
awk 'BEGIN {print srand()}'

How does it compare to the values in your file? What would be the difference of $5 and DT?
# 13  
Code:
kruz@ces-lt-it-kg:~$ awk 'BEGIN {print srand()}'
1
kruz@ces-lt-it-kg:~$

So i tried substituting srand() with an external date variable, same results.



Code:
kruz@ces-lt-it-kg:~$ cat test | awk -v test="$(date +%s)" 'BEGIN { DT = $test - 7776000}; $5 < DT'
kruz@ces-lt-it-kg:~$

Doing the math DT = 1573594249, which is greater than 1572283447.819 ($5), so it should be outputting the line.


I ran through this outside of awk, and one thing I noticed, when I assigned test="$(date +%s)" and called test, it returned;


Code:
kruz@ces-lt-it-kg:~$ test="$(date +%s)"
kruz@ces-lt-it-kg:~$ $test
1581370249: command not found
kruz@ces-lt-it-kg:~$


Last edited by beyondmondays; 02-10-2020 at 06:17 PM..
# 14  
Not a common awk implementation.


Good approach. Drop the $ before test inside awk:

Code:
$ awk -v test="$(date +%s)" 'BEGIN { DT = test - 7776000}; $5 < DT' file
 TAPEARCHIVES 1572970010.744 arn:aws:storagegateway:us-east-2:391499008633:tape/WEEK5B7EFA WEEK5B7EFA 1572283447.819 2748779069440 ARCHIVED 2738042187776




EDIT: You could even try
Code:
awk -v DT="$(date +%s -d"90 days ago")" '$5 < DT' file


Last edited by RudiC; 02-11-2020 at 08:47 AM..
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