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Help required with a file rename shell script

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Top Forums Shell Programming and Scripting Help required with a file rename shell script
# 8  
Old 06-25-2019
The probelm with a *${var}_* glob is that it is missing a leading anchor.
E.g. $var==2795 will match 002795_001.jpg and 012795_001.jpg Smilie
Reason enough to go for the less efficient but correct `ls | grep` and a ^0* anchor in the RE.
This User Gave Thanks to MadeInGermany For This Post:
tayyabq8
# 9  
Old 06-26-2019
Thanks to everyone, great solutions, and discussion. I'll try all of these out and let you know if I need any further help. I'll also post here my modified script which will go into production. Apologies again for the initial confusion. Have a great day ahead.
# 10  
Old 07-24-2019
Quote:
Originally Posted by MadeInGermany
The probelm with a *${var}_* glob is that it is missing a leading anchor.
E.g. $var==2795 will match 002795_001.jpg and 012795_001.jpg Smilie
Reason enough to go for the less efficient but correct `ls | grep` and a ^0* anchor in the RE.
I was thinking that bash Extended globbing and nullglob could be the solution to this, without the efficiency hit:

Code:
awk '
NR >= 2 {
  CMD="bash -O extglob -O nullglob -c \"printf \\\"%s\\n\\\" *(0)" $3 "_*.jpg\""
  while (CMD | getline FN && length(FN)) {
...

However, this still ends up invoking sh and then bash, which is only slightly better than sh ls and grep. The complexity (all those backslashes!) and reliance on bash make this more an academic solution rather than something I'd be inclined to use in the real world.
This User Gave Thanks to Chubler_XL For This Post:
drl
# 11  
Old 08-26-2019
It worked - Require one small modification
Quote:
Originally Posted by RudiC
No surprise. Your post #1 input sample provided the wrong structure, contained wrong data, and the sample file names didn't reflect reality either. What would you expect? With your "revised" data and input, try
Code:
awk '
NR >= 2 {("ls -x *" $3 "*.jpg") | getline L
         gsub (/[       ]+/, ",", L)
         LB = L
         gsub (/0+|.jpg/, "", L)
         gsub ($3, $2, L)
         $0 = $0  L
              split (LB, T1)
         n  = split (L,  T2)
         for (; n; n--) OUT = OUT sprintf ("echo mv -- %s %s\n", T1[n], T2[n] ".jpg")
        }
1
END     {system (OUT)
        }
' FS=, file
Full Registration,VIN,Stock ID,Mileage,InternalTrim,Description,Warranty,FranchiseApproved,RegistrationDate,Featured,NewVehicleType,Used stock images
2653BA,WDD1173461N6437866,2795,19434,Leather trim,A Class,Y,Y,19/09/2018,N,CAR,WDD1173461N6437866_1,WDD1173461N6437866_2,WDD1173461N6437866_3
8874MS,WDD1173461N6494217,2745,15452,Leather trim,A Class,Y,Y,19/09/2018,N,CAR,WDD1173461N6494217_1,WDD1173461N6494217_2
mv -- 002795_003.jpg WDD1173461N6437866_3.jpg
mv -- 002795_002.jpg WDD1173461N6437866_2.jpg
mv -- 002795_001.jpg WDD1173461N6437866_1.jpg
mv -- 002745_002.jpg WDD1173461N6494217_2.jpg
mv -- 002745_001.jpg WDD1173461N6494217_1.jpg


The first three lines are your target .csv file printed to stdout. The remaining 6 lines are the test output from the system call; remove the echo from the sprintf command to really have the files renamed.




EDIT: Slight simplification:



Code:
awk '
NR >= 2 {CMD = "ls *" $3 "*.jpg"
         while (1 == CMD | getline FN)
                {FNN = FN
                 gsub (/0+|.jpg/, "", FNN)
                 gsub ($3, $2, FNN)
                 $0 = $0 FS FNN
                 OUT = OUT "echo mv -- " FN " " FNN ".jpg\n"
                }
         close (CMD)
        }
1
END     {system (OUT)
        }
' FS=, file

Hi RudiC,

I used your simplified method and it worked fine, only one trouble I have is that the script doesn't work if stock ID has "0" in it, for example, it will not work if the image file name is "002501_001.jgp" please note that from character 3rd to 6th character is stock ID and can contain "0" in it, can you please modify your provided script to cater to this need? This will be a really great help. Many thanks in advance.

Regards,
Tayyab
Last edited by tayyabq8; 08-26-2019 at 04:41 AM..
# 12  
Old 08-26-2019
Would it suffice to "anchor" the gsub search pattern like
Code:
gsub (/^0+|.jpg/, "", FNN)

? Be aware that the files' sequence number will have leading zeroes, then.
This User Gave Thanks to RudiC For This Post:
tayyabq8
# 13  
Old 08-26-2019
Hi RudiC,

Yes I thought about it and yes anchoring alone will not help as the sequence numbers will have leading zeros as mentioned by yourself, any other advice, please. Many thanks once again.

Regards,
Tayyab
# 14  
Old 08-26-2019
OK, add
Code:
sub  (/_0+/, "_", FNN)

just below the first gsub.
This User Gave Thanks to RudiC For This Post:
tayyabq8
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