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Command works at command line but not from cron

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# 1  
Old 05-29-2019
Command works at command line but not from cron
Oracle Linux 6.
Trying to set up a simple monitoring of memory usage. This command does exactly what I want at the command line:

Code:
echo $(date +%Y-%m-%d" "%H:%M:%S) $(grep PageTables /proc/meminfo) >> /home/oracle/meminfo.log

But when I put it in my crontab:

Code:
* * * * *  echo $(date +%Y-%m-%d" "%H:%M:%S) $(grep PageTables /proc/meminfo) >> /home/oracle/meminfo.log

It fails and I get this in my mail

Code:
/bin/sh: -c: line 0: unexpected EOF while looking for matching `)'
/bin/sh: -c: line 1: syntax error: unexpected end of file

# 2  
Old 05-29-2019
man crontab yields :
Code:
The ``sixth'' field (the rest of the line) specifies the command to be run.  The entire command portion of the line, up to a newline  or  %
       character,  will be executed by /bin/sh or by the shell specified in the SHELL variable of the cronfile.  Percent-signs (%) in the command,
       unless escaped with backslash (\), will be changed into newline characters, and all data after the first % will be sent to the  command	as
       standard input

This User Gave Thanks to vgersh99 For This Post:
edstevens
# 3  
Old 05-29-2019
vgersh99 - that was it. Thanks for the assist.
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