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Transpose the 2nd coloumn in every fourth row three times....

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Top Forums Shell Programming and Scripting Transpose the 2nd coloumn in every fourth row three times....
# 1  
Old 01-24-2019
Transpose the 2nd coloumn in every fourth row three times....
I have several csv files, each hundreds of rows with the following layout

Code:
"","SEQ ID No.  1 Subject # 20"
"BPM neg.:",68.83
"BPM normal:",68.48
"SEQ ID No.  1 Subject # 20",79.33
"","SEQ ID No.  10 Subject # 20"
"BPM neg.:",68.05
"BPM normal:",68.58
"SEQ ID No.  10 Subject # 20",81.63
"","SEQ ID No.  17 Subject # 20"
"BPM neg.:",71.06
"BPM normal:",71.19
"SEQ ID No.  17 Subject # 20",81.99

I would need the first and fifth and ninth and.... row be transposed into a third coloumn three times giving me this output:


Code:
"BPM neg.:",68.83"","SEQ ID No.  1 Subject # 20"
"BPM normal:",68.48"","SEQ ID No.  1 Subject # 20"
"SEQ ID No.  1 Subject # 20",79.33"","SEQ ID No.  1 Subject # 20"
"BPM neg.:",68.05"","SEQ ID No.  10 Subject # 20"
"BPM normal:",68.58"","SEQ ID No.  10 Subject # 20"
"SEQ ID No.  10 Subject # 20",81.63"","SEQ ID No.  10 Subject # 20"
"BPM neg.:",71.06"","SEQ ID No.  17 Subject # 20"
"BPM normal:",71.19"","SEQ ID No.  17 Subject # 20"
"SEQ ID No.  17 Subject # 20",81.99"","SEQ ID No.  17 Subject # 20"

Many thanks,....

Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!
Last edited by RudiC; 01-24-2019 at 05:56 PM.. Reason: Added CODE tags.
# 2  
Old 01-24-2019
Welcome to the forum.


Any attempts / ideas / thoughts from your side?
# 3  
Old 01-24-2019
OK, calling it a day, now. Before leaving - how about this:


Code:
$ awk '!((NR-1)%4) {TMP = $0; next} {print $0 TMP}'  file
"BPM neg.:",68.83"","SEQ ID No.  1 Subject # 20"
"BPM normal:",68.48"","SEQ ID No.  1 Subject # 20"
"SEQ ID No.  1 Subject # 20",79.33"","SEQ ID No.  1 Subject # 20"
"BPM neg.:",68.05"","SEQ ID No.  10 Subject # 20"
"BPM normal:",68.58"","SEQ ID No.  10 Subject # 20"
"SEQ ID No.  10 Subject # 20",81.63"","SEQ ID No.  10 Subject # 20"
"BPM neg.:",71.06"","SEQ ID No.  17 Subject # 20"
"BPM normal:",71.19"","SEQ ID No.  17 Subject # 20"
"SEQ ID No.  17 Subject # 20",81.99"","SEQ ID No.  17 Subject # 20"

These 3 Users Gave Thanks to RudiC For This Post:
MadeInGermany Neo nezabudka
# 4  
Old 01-25-2019
Many thanks... and yes I tried a little sed, since I cannot seem to get the hang of awk...I will look for a tutorial though, sinc eI know that it is rude to just demand an answer without making an effort...
# 5  
Old 01-25-2019
Here is in sed
Code:
sed -n '1~4 {h;n};G;s/\n/ /p' file

These 3 Users Gave Thanks to nezabudka For This Post:
MadeInGermany Neo RudiC
# 6  
Old 01-25-2019
I would prefer awk here.
Of course it is doable in sed.
The N command appends the next input line (separated by a \n character) to the input buffer.
Do that 3 times, then do a big substitution:
Code:
sed 'N;N;N;s#\([^\n]*\)\n\([^\n]*\)\(\n[^\n]*\)\(\n[^\n]*\)#\2\1\3\1\4\1#' file

The first \( \) captures line1 and is the \1 in the substitution string
The second \( \) captures line2 and is the \2 in the substitution string
The next two \( \) capture line3 and line4 including their preceding \n character (that prints as a newline), they are \3 and \4 in the substitution string.
This User Gave Thanks to MadeInGermany For This Post:
Neo
# 7  
Old 01-25-2019
The 1~4, every 4 lines, is specific to GNU sed. It is very useful here, because sed normally has no means of "counting" things.
If by this you recognize the line to save, then you can use the hold buffer, and append it in all the following lines.
If there is a special pattern, then it also works with a standard sed (and Unix sed). For example "", at the begining of the line:
Code:
sed '/^"",/ {h;d;};G;s/\n//' file

These 3 Users Gave Thanks to MadeInGermany For This Post:
Neo nezabudka RudiC
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