How to pass variable from one function to another function?


 
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# 1  
Old 01-14-2019
How to pass variable from one function to another function?

Code:
updateEnvironmentField() {
	
	      linewithoutquotes=`echo $LINE | tr -d '"'`
             b()
}

I want to pass variable named $linewithoutquotes to another method called b(), which is called from updateEnvironmentField() method. How to do the above requirement with shell script
This User Gave Thanks to pottic For This Post:
# 2  
Old 01-14-2019
Quote:
Originally Posted by pottic
Code:
updateEnvironmentField() {
	
	      linewithoutquotes=`echo $LINE | tr -d '"'`
             b()
}

I want to pass variable named $linewithoutquotes to another method called b(), which is called from updateEnvironmentField() method. How to do the above requirement with shell script
First: you definitely shouldn't use backticks any more and the use of echo ... | tr ... is overly complicated. You can do:

Code:
linewithoutquotes="${LINE//\"/}"

To pass it to another function pass it as an argument:

Code:
b ()
{
     passedline="$1"
     echo "inside b(), passed line is: $passedline"
}


updateEnvironmentField()
{
     linewithoutquotes="${LINE//\"/}" 
     b "$linewithoutquotes"
}

I hope this helps.

bakunin
These 2 Users Gave Thanks to bakunin For This Post:
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