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1. UNIX for Dummies Questions & Answers
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
Discussion started by: pchegoor
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2. Shell Programming and Scripting
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
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3. UNIX for Dummies Questions & Answers
Hello,
I am trying to show today's date and time in a better format than ‘date' (Using positional parameters). I found a command mktime and am wondering if this is the best command to use or will this also show me the time elapse since 1/30/70? Any help would be greatly appreciated, Thanks... (3 Replies)
Discussion started by: citizencro
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4. Shell Programming and Scripting
Hello Experts,
How do i get date after 5 days from current date in YYYYMMDD format?
How do you compare date in YYYYMMDD format?
Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies
5. Shell Programming and Scripting
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Discussion started by: sunil087
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6. Shell Programming and Scripting
I am testing a script and need to change the system date to Nov 30 2009. I cannot seem to find a way to do this other than TZ command but it does not seem to work correctly.
I tried TZ=GMT+168 date but it is returning todays date
Mon Dec 7 19:48:11 GMT 2009
...instead of Nov 30 2009
I... (4 Replies)
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7. UNIX for Dummies Questions & Answers
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Discussion started by: figaro
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8. Shell Programming and Scripting
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
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9. Shell Programming and Scripting
why
date -d "19010101" gets error " date: invalid date `19010101' "
but
date -d "19020101" is fine?
Any approach to fix that?
Thank you. (8 Replies)
Discussion started by: freizl
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10. UNIX for Advanced & Expert Users
Hi ,
I have written a shell script that takes the current date on the server and stores it in a file.
echo get /usr/home/data-`date '+%Y%d'`.xml> /usr/local/sandeep/GetFILE.ini
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DATETIMEIMMUTABLE.FORMAT(3) 1 DATETIMEIMMUTABLE.FORMAT(3)
DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTimeImmutable.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO
date(3).
PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)