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Print every alternate column in row in a text file

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# 1  
Old 10-30-2018
Print every alternate column in row in a text file
Hi,

I have a comma separated file. I would like to print every alternate columns into a new row.



Example input file:
Code:
Name : John, Age : 30, DOB : 30-Oct-2018


Example output:
Code:
Name,Age,DOB
John,30,30-Oct-2018

Last edited by vgersh99; 10-30-2018 at 01:33 PM..
# 2  
Old 10-30-2018
Code:
echo 'Name : John, Age : 30, DOB : 30-Oct-2018' | awk -F'[:,]' '{for(i=2;i<=NF;i=i+2) printf("%s%s", $i,(i+2>NF)?ORS:OFS)}' OFS=,

# 3  
Old 10-30-2018
Thanks. It worked. But header is missing
# 4  
Old 10-30-2018
Quote:
Originally Posted by Lini
Thanks. It worked. But header is missing
This is left an exercise for the OP.
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