Shell Programming and Scripting

I have the string:

Code:

XXXX.YYYY_ZZZ.20180724.01.txt

I need to get rid of .txt and get full four parts

Code:

XXXX.YYYY_ZZZ.20180724.01

I did:

Code:

CTL=`echo XXXX.YYYY_ZZZ.20180724.01.txt | rev | cut -d"." -f4 | rev`

But got only

Code:

YYYY_ZZZ

What should I do to get all four parts of that string?


Thanks for contribution

Try

Code:

str=XXXX.YYYY_ZZZ.20180724.01.txt
CTL=${str%.*}

--
Note: this example is using parameter expansion

It works, but I have a Korn shell. Are you sure it will work with Korn shell?
I believe I can use `awk -F"." {'print $5.$4.$3.$2'}`


str%. works because of

Code:

#!/bin/ksh

at the beginning of the script. Seems like it is csh.

Please advise


Thanks for contribution

Looking at your recent posts, it seems you should get your act together and find out what shell you REALLY use - and tell people in here reliably.



For your unsatisfying code in post#1, try a field range for cut:

Code:

echo XXXX.YYYY_ZZZ.20180724.01.txt | cut -d"." -f1-4
XXXX.YYYY_ZZZ.20180724.01

This works in the Bourne shell and any shell derived from it: ksh88, ksh93, bash. See the man page and llok for "parameter expansion" to find out more about these constructs.

Of course what Scrutinizer has suggested is the preferred way to do it because it doesn't need to spawn a new process. To show you that many other (not as resource-preserving but still working) ways exist: use the basename utility. If it is provided a second argument it interprets this as extension and eventually cuts off this from the end of a filename:

Code:

$ basename some_file.ext .ext
some_file

I hope this helps.

bakunin