How can I apply 'date' command to specific columns, in a BASH script?

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LEARN ABOUT PHP

date_parse_from_format

DATE_PARSE_FROM_FORMAT(3)						 1						 DATE_PARSE_FROM_FORMAT(3)

date_parse_from_format - Get info about given date formatted according to the specified format

SYNOPSIS

       array date_parse_from_format (string  $format, string  $date)

DESCRIPTION

	Returns associative array with detailed info about given date.

PARAMETERS

	      o $format
		- Format accepted by DateTime.createFromFormat(3).

	      o $date
		- String representing the date.

RETURN VALUES

	Returns associative array with detailed info about given date.

EXAMPLES

       Example #1

	      date_parse_from_format(3) example

	      <?php
	      $date = "6.1.2009 13:00+01:00";
	      print_r(date_parse_from_format("j.n.Y H:iP", $date));
	      ?>

	      The above example will output:

	      Array
	      (
		  [year] => 2009
		  [month] => 1
		  [day] => 6
		  [hour] => 13
		  [minute] => 0
		  [second] => 0
		  [fraction] =>
		  [warning_count] => 0
		  [warnings] => Array
		      (
		      )

		  [error_count] => 0
		  [errors] => Array
		      (
		      )

		  [is_localtime] => 1
		  [zone_type] => 1
		  [zone] => -60
		  [is_dst] =>
	      )

SEE ALSO

       DateTime.createFromFormat(3), checkdate(3).

PHP Documentation Group 												 DATE_PARSE_FROM_FORMAT(3)

Shell Programming and Scripting