Shell Script run curl command calling cyber-Ark RESTAPI


 
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Old 05-09-2018
Display Shell Script run curl command calling cyber-Ark RESTAPI

Hi All,

We have a requirement to Integrate Cyber-Ark with Informatica .

Basically cyberark will contain the username and password for Database.

First step will be
1)In shell Script run curl command calling cyber-Ark RESTAPI requesting the credentials and store the secret in a variable.

Could someone help us how to achieve the above.

Thanks
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CURLOPT_PRIVATE(3)					     curl_easy_setopt options						CURLOPT_PRIVATE(3)

NAME
CURLOPT_PRIVATE - store a private pointer SYNOPSIS
#include <curl/curl.h> CURLcode curl_easy_setopt(CURL *handle, CURLOPT_PRIVATE, void *pointer); DESCRIPTION
Pass a void * as parameter, pointing to data that should be associated with this curl handle. The pointer can subsequently be retrieved using curl_easy_getinfo(3) with the CURLINFO_PRIVATE option. libcurl itself never does nothing with this data. DEFAULT
NULL PROTOCOLS
All EXAMPLE
CURL *curl = curl_easy_init(); struct private secrets; if(curl) { struct private *extracted; curl_easy_setopt(curl, CURLOPT_URL, "http://example.com"); /* store a pointer to our private struct */ curl_easy_setopt(curl, CURLOPT_PRIVATE, &secrets); curl_easy_perform(curl); /* we can extract the private pointer again too */ curl_easy_getinfo(curl, CURLINFO_PRIVATE, &extracted); } AVAILABILITY
Added in 7.10.3 RETURN VALUE
Returns CURLE_OK if the option is supported, and CURLE_UNKNOWN_OPTION if not. SEE ALSO
CURLOPT_VERBOSE(3), CURLOPT_STDERR(3), libcurl 7.54.0 February 03, 2016 CURLOPT_PRIVATE(3)