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Grep and neglect a specific string

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Top Forums Shell Programming and Scripting Grep and neglect a specific string
# 1  
Old 04-09-2018
Grep and neglect a specific string
Hi,

I have a file with "n" number of lines. I need to get rid of a specific line having a specific string from the file. I tried some possibilities but not successful.

For ex: in a file named "test"
hope should be removed along with the line.

Code:
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:get/the/hope/to/work:success
LIB_WORK=/lets/hope/for/the/best \

output should be
Code:
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:success

# 2  
Old 04-09-2018
What did you try, and what wrong output did you get?
# 3  
Old 04-09-2018
Quote:
Originally Posted by ricky-row
. . . get rid of a specific line having a specific string
.
.
.
hope should be removed along with the line.
.
.
.
Unclear: you write you want to remove line(s) but in your sample, only parts of the line are removed. Pls. clarify.
# 4  
Old 04-10-2018
@RudiC My requirement is both as you could see from the first line "hope" lies between :*hope*: the other line doesn't have any : so, it should remove the entire content.

@MadeInGermany
I have used the regex for replacing words with others, not in an expected way. so, I am not aware of the pattern to be used.

Code:
sed -i -re "s,hope,,g" test

Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!
Last edited by RudiC; 04-10-2018 at 04:32 AM.. Reason: Added CODE tags.
# 5  
Old 04-10-2018
Like so?
Code:
sed 's/\(:*\)[^:]*hope[^:]*:*/\1/g; /^$/d' file
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:success

# 6  
Old 04-10-2018
Hi RudiC
This is works really great when the content is in two seperate lines as
Code:
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:get/the/hope/to/work:success

LIB_WORK=/lets/hope/for/the/best \

Code:
:~/Desktop/test1$ sed 's/\(:*\)[^:]*hope[^:]*:*/\1/g; /^$/d' te
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:success

but some output come within a single line, in that case, it loses some data,
Could you give a modification according to that

Code:
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:get/the/hope/to/work:success LIB_WORK=/lets/hope/for/the/best \

Code:
:~/Desktop/test1$ sed 's/\(:*\)[^:]*hope[^:]*:*/\1/g; /^$/d' te
PASS=test1/worked:fail/withthe/test/:go-to-school/grab/some:


if some explanation provided on the logic, it will much better to me to understand make use of it in, instead of wasting your valuable time.

---------- Post updated at 01:33 PM ---------- Previous update was at 01:20 PM ----------

Hi

If the regex is given in two different conditions too, its welcome.
Like one condition check for
Code:
:

as delimiter and remove the content with along with on delimiter
Code:
hope

2nd can check for the
Code:
hope

and if no delimiter was there it can delete the entire content
Code:
LIB_WORK=/lets/hope/for/the/best

Adding this to make clear in need
Last edited by ricky-row; 04-10-2018 at 04:51 AM.. Reason: code not visible
# 7  
Old 04-10-2018
It is usually best and most efficient for all parties to carefully phrase the request in the first place, cogitating all the possible ramifications e.g. difference in structures and positions in files. Better than letting drip in information droplet by droplet after a solution was found for the first but non-fitting sample.

The easiest way would be to force the long lines into several independent ones:
Code:
tr ' ' '\n' < file | sed ...

The logics lie in the regex: find a string of zero or more colons (parenthesized for later "back reference") then any number of non-colons, the "hope" string, non-colons again, and finally zero or more colons. Replace by the first colon if exists else the empty string (i.e. remove)
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