Bash for loop array


 
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Old 03-13-2018
Bash for loop array

Hi there,

A bit new to bash and am having an issue with a for loop. I look for filenames in a specified directory and pull the date string from each meeting a certain criteria, and then would like to make a directory for each date found, like this:

Code:
search 20180101.gz 20180102.gz 20180103.gz
store 20180101 20180102 20180103 in an array
mkdir for each value found

The problem is that the mkdir part is only making a directory for the first value found.

This is the actual code:

Code:
for line in $(echo ${DPPATH}/${DBNAME}*.dmp.gz ${MTIMECMD} -type f |grep -Eo '[[:digit:]]{8}')
do
find ${DPPATH}/${DBNAME}*.dmp.gz ${MTIMECMD} -type f -exec /usr/local/bin/aws s3 mv {} "s3://"${S3BUCKET}/export_area/${DBNAME}/${line}/ \;
done

Any input would be greatly appreciated.

Last edited by jim mcnamara; 03-13-2018 at 04:16 PM..
 
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