Shell Programming and Scripting

Hi UnixGurus

Could you please help me with the below scenario.

Code:

SERVER1=abc.ins.com
SERVER2=exy.ins.com
PATH=/home/oracle/backup/
USER=oracle

I want to sync $PATH from $SERVER1 to $SERVER2. I used the below command and run the command from $SERVER1

Code:

/usr/bin/rsync -arv -e ssh $PATH $USER@$SERVER2:/$PATH

Here I faced the below problem.

$SERVER2 has login profile to list all applications (directories) and prompts the user to select from it.

$SERVER2 login profile ("select" command in the profile) sample output:

Code:

Welcome to exy.ins.com

1) APP1
2) APP2
3) APP3
4) APP4
5) APP5
6) APP6
7) APP7
#? 1

When I run RSYNC command I am getting the below error;

Code:

tput: No value for $TERM and no -T specified
protocol version mismatch -- is your shell clean?
(see the rsync man page for an explanation)
rsync error: protocol incompatibility (code 2) at compat.c(171) [sender=3.0.6]

When I updated login profile in $SERVER2 (commented out "select" command), the RSYNC command works fine.

Is there any way to make RSYNC work from $SERVER1 without making any changes to $SERVER2 profile? (Any option to supply for not to invoke $SERVER2 login profile using RSYNC)

If your shell (which, btw, you fail to mention) provides the -i option flag, you could evaluate that (with ?-) and skip the select command.