Shell Programming and Scripting

I have doubts with the following command:

Code:

% find "$1" -name "*.html" -print0 | sort -zn | xargs -r -0 -n 1 sh -c 'echo "Dumping file: $2" >> "$1"; w3m "$2" >> "$1" 2>&1 ' sh "$2"

I have doubts in the input arguments value i.e. $0, $1, $2...

Step by step:
1.- % find "$1" -name "*.html" -print0 | ...
where:
- $1 is the name of the directory to search on
2.-

Code:

% ...| ... sh -c 'echo "Dumping file: $2" >> "$1"; w3m "$2" >> "$1" 2>&1' sh "$2"

where:
- $0 is sh -c
- $1 is the same as $1 in the step 1 ??? Why???
- $2 is the htmlA
- $3 is the htmlB and so on with $4, $5 etc.
3.- Finally, .. sh "$2" makes a shift
The value in $3 will be now $2

Is my understanding correct? How is the value of $1 taken?


Thanks.

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