Shell Programming and Scripting

Hi all,

I have a script which gets its input from a text file (file.txt) and processes each line within a loop.

I have a counter which increases by one and I want something to happen every 7th, 14th, 21st, etc. line read.

Currently the code looks and works perfectly like this:

------------------------------------------
count="1"

while read WORKSTATION
do
if [ $count -eq 7 ] || [ $count -eq 14 ] || [ $count -eq 21 ] ||\
[ $count -eq 28 ] || [ $count -eq 35 ] ; then

some code here ....

((count=count+1))
fi

done < file.txt ;
------------------------------------------

However, it doesn't look beautiful and with that many conditional statements (I shortened it, it goes further than just 35) I'm, looking for a more elegant solution.
I have tried this

if [ $count -eq '[7,14,21,28,35]' ] ; then

but it doesn't work...

Does anyone know the correct syntax - or is this not possible?

Many thanks in advance!

Cheers,
Tom

If you include what the 7th line is (is there a repetitive pattern, etc) and what you are trying to do with/after that line, maybe there's a one-liner sed or awk solution.

Code:

$ cat mod
#! /usr/bin/ksh
count=1
while ((count < 50 )) ; do
        if (( !(count%7) )) ; then
                echo count = $count
        fi
        ((count=count+1))
done
exit 0
$ ./mod
count = 7
count = 14
count = 21
count = 28
count = 35
count = 42
count = 49
$

Many thanks for the fast replies!

Perderabo's solution works like a charm