I am building a parent script which will call three scripts internally and i would like to run them in sequence manner, i.e. once previous script is successful then only i need to proceed with next else need to fail. I am running in bash mode and flavour is sun
I need to better solution to handle this and also i would require if rerun the main_script.sh then the those scripts which are executed successfully shouldn't execute once again. Like for eg. if script2.sh failed and if i run the main script i shouldn't run script1.sh rather than stating the message like script1 already completed hence proceeding with script2.sh
Last edited by Master_Mind; 08-14-2017 at 11:14 PM..
Reason: change in code
I am building a parent script which will call three scripts internally and i would like to run them in sequence manner, i.e. once previous script is successful then only i need to proceed with next else need to fail. I am running in bash mode and flavour is sun
I need to better solution to handle this and also i would require if rerun the main_script.sh then the those scripts which are executed successfully shouldn't execute once again. Like for eg. if script2.sh failed and if i run the main script i shouldn't run script1.sh rather than stating the message like script1 already completed hence proceeding with script2.sh
There are a lot of pieces here that don't quite seem to fit. I assume that when you say "the flavour is sun" you mean that you are running an old system from Sun Microsystems, Inc. If that is true, then you are running script1.sh, script2.sh, and script3.sh with an old Bourne shell; not with bash.
Assuming that this script is being run by bash or ksh (or some other shell that includes POSIX standard arithmetic substitutions; which does not include /bin/sh on Solaris 10 systems), the following untested code might do what you want:
although it is totally untested. It assumes that you always run this script in the same directory and uses a file named status in that directory to keep track of the last job that was successfully completed (and when that job last completed successfully).
I hope this gives you some idea of how you could approach this problem and gives you something you can modify to get what you want to work in your environment.
In your case if i rerun the main_script the first script also exuecuting when script2.sh has failed. In my status i can see 1 but since you are using below code its getting replaced
In your case if i rerun the main_script the first script also exuecuting when script2.sh has failed. In my status i can see 1 but since you are using below code its getting replaced
From your post #6 it sounds like you found the problem, but for the record, the code I suggested should work as explained below...
The first time you run that script (or if the file status does not exist), the above statement creates a status file initialized saying that step 0 has been completed. When script1.sh completes successfully, the statements:
increment job to 1 and rewrites the status file to contain that 1 and the current date and time stamp.
If script2.sh then fails, the script will exit without further updating the contents of status. The next time you start the script (as long as you haven't removed status and you run it in the same directory), the statement:
will find that the file status already exists so it will not update its contents and the following read statement:
will set job to 1. And since the following test:
will find that 1 is not equal to 0, the following code to run test1.sh will not be run again until script2.sh and script3.sh have both run successfully (or you manually remove the file status or run it in a different directory).
This User Gave Thanks to Don Cragun For This Post:
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