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Source functions from variable

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# 1  
Old 04-28-2017
Source functions from variable
I have a functions file containing functions:

file.functions:
Code:
myTest () {
echo "MYPWD=$(echo $(pwd))"
echo "MYLOGNAME=${LOGNAME}"
}
myCar () {
echo "MYDATE=$(date)"
echo "MYUPTIME=$(uptime)"
}

i know i can source this file in another script using something similar to this:

Code:
source /tmp/file.functions
or
. /tmp/file.functions

however, suppose I have the content of /tmp/file.functions in a variable, how can I source it?

i.e.

Code:
MyFunctions=$(cat /tmp/file.functions)

# 2  
Old 04-28-2017
Instead of MyFunctions=$(cat /tmp/file.functions), why not just use MyFunctions=/tmp/file.functions and then use:
Code:
source "$MyFunctions"

or
Code:
. "$MyFunctions"

This User Gave Thanks to Don Cragun For This Post:
SkySmart
# 3  
Old 04-28-2017
Quote:
Originally Posted by Don Cragun
Instead of MyFunctions=$(cat /tmp/file.functions), why not just use MyFunctions=/tmp/file.functions and then use:
Code:
source "$MyFunctions"

or
Code:
. "$MyFunctions"

ok, i provided the cat example to depict functions being in a variable.

in the case that am working on, the functions will be in a variable. i only catted them in the example to show precisely what i was aiming for.

i need to source a variable.

ok., let me put a different way.

Code:
MyFunctions='
myTest () {
echo "MYPWD=$(echo $(pwd))"
echo "MYLOGNAME=${LOGNAME}"
}
myCar () {
echo "MYDATE=$(date)"
echo "MYUPTIME=$(uptime)"
}
'

can i source this variable now?
# 4  
Old 04-29-2017
Hi,
this is just another way.

You only nee to add a semicolon at the end of each command.

Code:
myTest () { echo "MYPWD=$(echo $(pwd))"; echo "MYLOGNAME=${LOGNAME}"; } myCar () { echo "MYDATE=$(date)"; echo "MYUPTIME=$(uptime)"; }

Then:

Code:
MyFunctions=$(cat /tmp/file.functions)

eval $MyFunctions

typeset -f myTest

myTest () { echo "MYPWD=$(echo $(pwd))" echo "MYLOGNAME=${LOGNAME}" }

Greetings!
Last edited by AbelLuis; 04-29-2017 at 12:58 AM..
This User Gave Thanks to AbelLuis For This Post:
SkySmart
# 5  
Old 04-29-2017
Can I ask why you need to put functions into an "intermediate" container object? Doing what Don Cragun suggested is simpler and standard.

Your efforts will make code maintenance much harder. This may not apply to you, but don't confuse cool with good programming practice. The two are not always congruent.
# 6  
Old 04-29-2017
@jim mcnamara

I added that way because it was the original request.

Quote:
Originally Posted by SkySmart

however, suppose I have the content of /tmp/file.functions in a variable, how can I source it?

i.e.

Code:
MyFunctions=$(cat /tmp/file.functions)

Regards.
This User Gave Thanks to AbelLuis For This Post:
SkySmart
# 7  
Old 04-29-2017
i really need to be able to source functions however they are stored in a variable.

i understand it shouldnt be done this way. but i have my own need to do it this way.

doesnt look like its possible Smilie
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