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Add Delimiter after 2 decimal point for a particular column

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# 1  
Old 04-03-2017
Add Delimiter after 2 decimal point for a particular column
Hi All,
Please help for the following scenario where I want to add a delimiter after 2 decimal point integer.
Code:
Original Line
1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05000§762.59§00395§M§301223.0528§1165§2017-03-31 20:34:25

Expected Line
1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05000§762.59§00395§M§301223.05§28§1165§2017-03-31 20:34:25

After 2 decimal point I would like to add a delimiter "§", Above is just a single line, in actual it contains 17K rows. This need to apply the same to all rows.

Thanks.
# 2  
Old 04-03-2017
I was afraid that § being a two byte character would make things difficult, but (at least my) sed (sed (GNU sed) 4.2.2) seems to be locale aware. Try
Code:
sed 's/\(\.[0-9][0-9]\)\([^§]\)/\1§\2/g' file
1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05§000§762.59§00395§M§301223.05§28§1165§2017-03-31 20:34:25

Why, BTW, is 00005.05 NOT modified in your output sample?
Last edited by RudiC; 04-03-2017 at 10:13 AM..
# 3  
Old 04-03-2017
Using perl's negative lookbehind:
Code:
perl -pe 's/\.\d\d(?!§)/$&§/g' file

# 4  
Old 04-03-2017
Thanks Guy. I will reply the outcome after I tested.
# 5  
Old 04-03-2017
Quote:
Originally Posted by Scrutinizer
Using perl's negative lookbehind:
Code:
perl -pe 's/\.\d\d(?!§)/$&§/g' file

That's the negative lookahead assertion.
The negative lookbehind assertion would look like this:
Code:
(?<!regex)

# 6  
Old 04-03-2017
Thank You Guys,
However perl and sed solution provided will replace the first occurrence as well.
I found Rudic given sed solution has included 2nd occurrence, but it still change for the first.
I wish can see how perl to resolve this as well.
Code:
1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05000§762.59§00395§M§301223.0528§1165§2017-03-31 20:34:25

1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05§000§762.59§00395§M§301223.05§28§1165§2017-03-31 20:34:25

---------- Post updated at 09:05 PM ---------- Previous update was at 08:20 PM ----------

Hi Guys,
manage to get it resolve by minor change on the occurrence, instead of /g use /2 on the sed command we use.
Code:
  sed 's/\(\.[0-9][0-9]\)\([^§]\)/\1§\2/2'

  1007937820§L§2016-12-19§000000002§2018-02-01§2050-12-01§00395§M§146713.57§00005.05000§762.59§00395§M§301223.05§28§1165§2017-03-31 20:34:25

Hopes we can also know how it can be achieve by using perl command too.

Thanks So much you all the contribution.
# 7  
Old 04-04-2017
Indeed, that (non-) modification of the first occurrence was NOT specified in the first place, and I asked about what to do...
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