In my script i need to sleep for some seconds till the previous command exeuction is successful
Code:
#!/bin/bash
cp test.txt /direct/sub_dir
if [ "$?" = "0" ]; then
echo "file copied"
else
echo "file not copied"
sleep 5
exit 1
fi
i need to sleep for 5 seconds if the copy command fails and check till 10 times after 10th time the script will exit saying file not copied after attemping 10 times
What makes you think the system will continuously attempt to try to copy?
Your logic wont work like that, you need a loop for the copy that does 10 attempts or gets out of the loop if one is successful with the sleep in the loop
Yes i agree with you i need to do loop 10 times if it exeeds 10 times and still not able to copy due to some other issues like folder not exists, then exit with sleep. like how you suggested.
So would like to know how i can be able to do that
Yes i agree with you i need to do loop 10 times if it exeeds 10 times and still not able to copy due to some other issues like folder not exists, then exit with sleep. like how you suggested.
So would like to know how i can be able to do that
I am confused here. What is the need to exit and wait a few seconds for it to happen using sleep 5 . I really do not understand your logic.
vbe has already commented what you need so why not try a simple loop to see what happens.
I think this is what you might be after! NOTE! There is no capture of any errors/reports that get printed to 'stderr' or 'stdout'.
Try something basic and see if you understand the logic:-
Code:
#!/bin/sh
LOOPIT=1
while [ "$LOOPIT" -le 10 ]
do
echo cp file /drawer/subdrawer
RC=$?
# RC=1
if [ "$RC" -eq 0 ]
then
echo "Copy successful!"
exit 0
fi
sleep 1
LOOPIT=$(( LOOPIT + 1 ))
done
echo "Copy FAILED!"
exit 1
The first 'echo' is purely for checking and remove if you are happy and why did I comment out # RC=1 ?
I have used a 1 second sleep here purely for checking...
You are here to learn so try and tell us what you think is happening?
This User Gave Thanks to wisecracker For This Post:
Sorry for confusing you guys. I didnt reperesnt in correct way. Thanks guys
Exactly this is what i wanted i am trying to [perfom copy operation.After trying to make one attempt it will sleep for sometime. Like this it will try to attempt for 10 times. Post then if still not able to copy it will exit the script stating tried 10 attempts.
One more thing is there a way to break the loop if copy is successful
Code:
#!/bin/sh
LOOPIT=1
while [ "$LOOPIT" -le 10 ]
do
echo cp file /drawer/subdrawer
RC=$?
# RC=1
if [ "$RC" -eq 0 ]
then
echo "Copy successful!"
break
fi
sleep 1
LOOPIT=$(( LOOPIT + 1 ))
done
echo "Copy FAILED!"
exit 1
But after doing break its printing Copy Failed
i got it to do like this thanks guys
Code:
#!/bin/sh
LOOPIT=1
while [ "$LOOPIT" -le 10 ]
do
echo cp file /drawer/subdrawer
RC=$?
# RC=1
if [ "$RC" -eq 0 ]
then
echo "Copy successful!"
break
fi
sleep 1
LOOPIT=$(( LOOPIT + 1 ))
done
if [ $LOOPIT -gt 10]
then
echo "Copy FAILED!"
exit 1
fi
Last edited by Master_Mind; 03-16-2017 at 07:41 AM..
Reason: to update the script
Hi Master_Mind...
Why did you change exit 0 to break ?
Is this part of a greater script that is unknown to us?
If so then try this...
Code:
#!/bin/sh
LOOPIT=1
while [ "$LOOPIT" -le 10 ]
do
echo cp file /drawer/subdrawer
RC=$?
if [ "$RC" -eq 0 ]
then
echo "Copy successful!"
break
fi
sleep 1
LOOPIT=$(( LOOPIT + 1 ))
if [ "$LOOPIT" -eq 11 ]
then
echo "After $(( $LOOPIT - 1 )) attempts, copy FAILED!"
# 'exit 1' quits the program with an error code, $?, of 1.
exit 1
fi
done
echo '"break" brings you here!'
# More code...
This User Gave Thanks to wisecracker For This Post:
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03-16-2017
