Shell Programming and Scripting

HI
I need some help on this below one
Have summuary file coming on daily basis with list of file names and count ,if the summuary file not exist ,pool it for every 5 mins till it arrives .Once arrived remove first and last line from the file and check all the files in respective director all are exist it,If it exists compare count with file against file exist in OS ,if it matches for all the files then move it some other server .Can any help from any one ?

Regards,
MM

---------- Post updated at 01:44 AM ---------- Previous update was at 01:18 AM ----------

Take all the files from this test file and check whether all are exist ,if all are exist then move to some other direcotry

Example
summary.txt

Code:

 PASSIVELBS_xxx_ 1 
 PASSIVELBS_xxx_ 2 
 PASSIVELBS_xxx_ 3

Hi, what have you tried so far and where are you stuck?

Hi
want to check ,grep and sed cannot use single like ,i want to find **** lines in file,if exist only remove those lines .When i am doing the below check throwing error

Code:

CHECK_FILE=`egrep -i '******' ${BASE_PATH}/${FILENAME}|sed -i '1d;$d'`

sed: no input files

Code:

if [ -f  ${BASE_PATH}/${FILENAME} ] ; then
    awk ' index($1, "*")==1 {next} 
            {print} ' ${BASE_PATH}/${FILENAME}  > tmp.tmp
    mv tmp.tmp ${BASE_PATH}/${FILENAME}
fi

This deletes the lines you want deleted. Drop the mv command if you want to keep the file as it was. Your original code does not make sense to me. The CHECK_FILE variable will always be "empty".

Thanks jim,its working perfect.I need one more conditions to check
Let say summary.txt having 3 files but when checking only 2 files are available in that location ,ensure that 3 files should be exist before proceeding to another step .

Code:

summary.txt
========
PASSIVELBS_xxx_ 1 
PASSIVELBS_xxx_ 2
PASSIVELBS_xxx_ 3

PLEASE DON'T edit posts after people have replied to it, pulling the rug from under their feet (and here: yours as well) and rendering their efforts useless!

With your modifications of post#1, jim mcnamara's proposal becomes a pointless no-op.
And, BTW, grepping for a pattern like '****' as you do in post#3 won't work as expected because * is a regex multiplier (zero or more times) character. To remove starred and blank lines from your input, try

Code:

grep -v '\*\|^ \+$' file

The error in post#3 is due to you wanting sed to "edit-in-place" stdin from a pipe.

Re your new request: do you just want a file count of three, or should exactly those three listed files exist? If the former: are there always exactly two header lines to be skipped?

Hi ,
Below code is working fine,exit from loop if not matching .I need to be loop forever untill match both files count .Any help would be appereciated

Code:

summary=`cat ${BASE_PATH}/${FILENAME|wc -l`
check=`ls -l PASSIVELBS_xxx_*|wc -l`
while [ $summary != $check ];do 
echo "Summary files are $summary"
echo "Checksum files are $check"
echo "Files are not matching with checksum"
exit 1