Bash compere 2 numbers and know the diffrents


 
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# 1  
Old 03-07-2017
Bash compere 2 numbers and know the diffrents

Hi,

id like to know how i do this :
if i have 2 different numbers:


Quote:
A=110050
B=362544
if [ $A < $B ];
then echo ok.


so ok bash knows B is bigger then A but i like to know in how much ?
how can i calculate ?

how can i know what is their difference ?
like the way you know between 10 and 2 the difference is 8

Thanks.
# 2  
Old 03-07-2017
Hi,

A script like this would do the trick:

Code:
#!/bin/bash

A=110050
B=362544

if [ "$A" -gt "$B" ]
then
        let difference=$A-$B
        echo "$A is greater than $B"
        echo "The difference between them is $difference"
elif [ "$A" -lt "$B" ]
then
        let difference=$B-$A
        echo "$B is greater than $A"
        echo "The difference between them is $difference"
else
        echo "$A and $B are the same"
fi

Hope this helps.
# 3  
Old 03-07-2017
Code:
#!/bin/bash

A=110050
B=362544
(( C = A - B ))

[[ $A = $B ]] && { echo numbers are equal ; } || echo numbers differ by ${C#-}

This User Gave Thanks to rdrtx1 For This Post:
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