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How can I find "-" ni the string variable?

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Top Forums Shell Programming and Scripting How can I find "-" ni the string variable?
# 1  
Old 03-01-2017
How can I find "-" ni the string variable?
I have 100 strings, which have YYYYDDMMHHMMSS in it and only one is YYYYMMDD-HHMMSS.
I want to find that dash and replace it. If I check each string, using sed 's/-//g', it shows me warning that - is not found.
So I need if [ - found ];then sed 's/-//g', but I cannot find correct regular expression to find - in if statement.
Can somebody help me?
I am working on AIX and using Korn, c, or borh shell.
Last edited by rbatte1; 03-01-2017 at 11:45 AM.. Reason: Added ICODE tags
# 2  
Old 03-01-2017
Can you show us some sample input and the output from your attempts (wrapped in CODE tags) so we can see what you are getting?


Thanks,
Robin
# 3  
Old 03-01-2017
It is very difficult to believe that
- sed 's/-//g' should NOT replace any dashes found in a file (unless a similar but different locale character were used),
- sed would show an error message anywhere like something "is not found" in a substitute command,
provided that the data are supplied in a file or a pipe.
If the data are shell variables, sed were inappropriate; use parameter expansion instead.
# 4  
Old 03-01-2017
input
Code:
 dt=`date '+%Y%m%d-%H%M%S'`
echo "${dt}" =#20170301-110352
dash=`echo ${dt} | cut -c 9`
echo "dash ${dash}" # "-"
if [ "${dash}" = "-" ]
then
${dt1}=`echo ${dt} | sed 's/-//g'`
echo "DATE NOW IS ${dt1}"
fi

It gives the error
Code:
script[18]: =20170301110352: not found
DATE NOW IS

What is wrong?

---------- Post updated at 11:10 AM ---------- Previous update was at 11:07 AM ----------

RudiC,
I don't have file. I have variable, where is
20170301-110352 and I wont to find it and replace with //, i.e. I need to have timestamp like 20170301110352

---------- Post updated at 11:14 AM ---------- Previous update was at 11:10 AM ----------

Sorry, I found my error

below is working fine
Code:
if [ "${dash}" = "-" ]
then
        dt1=`echo ${dt} | sed 's/-//'` #don't need to put {} around dt1
        echo "DATE NOW IS ${dt1}"
fi


Moderator's Comments:
Mod Comment Seriously: PLEASE use CODE tags as required by forum rules!
Last edited by RudiC; 03-01-2017 at 12:20 PM.. Reason: Added CODE tags.
# 5  
Old 03-01-2017
Why don't you use your shell's "parameter expansion/pattern replacement"?
Code:
echo "$dt" "${dt//-}" 
20170301-171628 20170301171628

# 6  
Old 03-01-2017
I work on a very old version of UNIX - AIX. And there is a mess. Seems like we use c or korn shell, but in reality it is born shell.
Your statement gives me "${dt//-}": bad substitution always


Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!
Last edited by RudiC; 03-01-2017 at 12:37 PM.. Reason: Added CODE tags.
# 7  
Old 03-01-2017
Do you mean "Bourne shell" (= /bin/sh)?

How about reading the man page and applying some creativity, like
Code:
echo ${dt%-*}${dt#*-}
20170301173320
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