To find record having null value


 
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# 15  
Old 12-23-2016
Hello ginrkf,

So in awk if you want to pass shell arguments you can't pass those values like that, could you please try following(I haven't tested though).
Code:
cat script.ksh
a=$1
awk -vval="$a" -F"|" 'function verify(var){
                                        num=split(var, A);
                                        for(i in A){
                                                        if($A[i]){
                                                                        p++
                                                                 }
                                                   };
                                        if(num==p) {
                                                         print $0 " with file name: " FILENAME>> "correct_lines"
                                                   };
                                        if(num!=p) {
                                                         print $0 " with file name: " FILENAME >> "incorrect_lines"
                                                   }
                                        p=""
                               }
           FILENAME=="SAMPLE_FILE"   {
                                        verify(val);
                               }
           '   SAMPLE_FILE

Also you have put -F"|" in above code just wanted to tell you it means you are setting delimiter as | but in your sample Input_file I couldn't see that, so if you have different Input_file which is having | as delimiter then it is ok else we have to see how the Input_file looks like.

Thanks,
R. Singh
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