How can i modify this script to echo an error msg and exit the script incase the user does not specify the -f option in the argument.
Out of a myriad of other possibilities: introduce a flag, set it to false initially, set it to true in the handling part of the "-f"-option and test for its status afterwards:
Code:
#!/bin/bash
local opt="" # when will you learn to declare what you use?
local file_in="" # input file
local -i lFUsed=0 # flag f-option was used = false
while getopts ":f:" opt; do
case $opt in
f)
file_in="$OPTARG"
# a test for the file being readable/existing would fit nicely here, no?
lFUsed=1 # change flag when -f was indeed used
;;
\?)
echo "Invalid option -$OPTARG" >&2
;;
esac
done
if ! (( lFUsed )) ; then
echo "no f-option was used, Aborting!." >&2
exit 1
fi
exit 0
bash-4.1$ more bl.sh
callme()
{
#!/bin/bash
local opt="" # when will you learn to declare what you use?
local file_in="" # input file
local -i lFUsed=0 # flag f-option was used = false
while getopts ":f:" opt; do
case $opt in
f)
file_in="$OPTARG"
# a test for the file being readable/existing would fit nicely here, no?
lFUsed=1 # change flag when -f was indeed used
;;
\?)
echo "Invalid option -$OPTARG" >&2
;;
esac
done
if ! (( lFUsed )) ; then
echo "no f-option was used, Aborting!." >&2
exit 1
fi
exit 0
}
callme
Now executing bl.sh as below.
Code:
./bl.sh -f hello.txt
no f-option was used, Aborting!.
Why is it giving error when it should have worked ?
Why is it giving error when it should have worked ?
Can you please tell me whats wrong ??
Yes: you have put everything - including the shebang line, which makes absoultely no sense - into a function and then called the function with no arguments. What is getopts supposed to work on when there are no options provided, hm?
You could have found that out easily yourself by putting an echo-statement here:
Code:
f)
file_in="$OPTARG"
# a test for the file being readable/existing would fit nicely here, no?
echo "now in -f option handling"
lFUsed=1 # change flag when -f was indeed used
;;
and you would have immediately noticed that this part was not even executed. You could also have put a testwise echo-statement into the while-loop and show the values of "$opt" and "$OPTARG" during executing which would have yielded the same information. Finally you could have tried the sample script UNMODIFIEDLY first before you tinkered with it.
Don't get me wrong, it is meant to be tinkered with. But trying to understand it first before doing experiments (like putting everything into a function) is usually a good idea.
i am reading line by line from a file as below
while IFS= read -r var
do
...
...
...
done < "hello.txt"
I added the keytool command in the do while loop as below.
while IFS= read -r var
do
...
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