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Filter pattern in grep command

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# 1  
Old 12-07-2016
Filter pattern in grep command
Hi,

I am having a file like below
Code:
hello how are you
hello dasdsadasdsadasdasdasdsadasddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
this aaaaaaa aaaaa aaaa
echo "This aaaa aaaaa aaa"

I need to display like below using grep
Code:
hello how are you
hello dasdsadasdsadasdasdasdsadasddddddddddddddddddddddddddddddddddddddd

i am using grep but need to display only first line in second matching pattern
Code:
grep hello test.log

# 2  
Old 12-07-2016
How about piping through cut -c, supplying the count of characters you need?
# 3  
Old 12-07-2016
Thanks for your suggestion i am unable to use it

Code:
grep hello test.log | cut -c 50

# 4  
Old 12-07-2016
Try
Code:
grep hello test.log | cut -c -50

This User Gave Thanks to RudiC For This Post:
rohit_shinez
# 5  
Old 12-07-2016
Perfect worked thanks
# 6  
Old 12-07-2016
Try also
Code:
grep -o 'hello.\{1,50\}' file

This User Gave Thanks to RudiC For This Post:
rohit_shinez
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