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Shell Programming and Scripting

FInd all string occurences

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# 8  
Old 12-04-2016
The -exec awk can be run several times; then the "Total" does not work as intended.
So the pipe must be there...
This User Gave Thanks to MadeInGermany For This Post:
RudiC
# 9  
Old 12-04-2016
Thanks for pointing that out. Try
Code:
find . -name "*.txt" -exec awk '{CNT[FILENAME]+= gsub (/ 0/, "&") - gsub (/"AC_STAT 0/, "&")} END {for (c in CNT) print c, CNT[c]}' {} + | awk '{TOT += $2} 1; END { print "Total", TOT}'

# 10  
Old 12-04-2016
Thank you, RUdi!

Which portion is my original search string though?

This portion?

Code:
(/ 0/

# 11  
Old 12-04-2016
Yes. You can also use " 0".
# 12  
Old 12-04-2016
Thank you!

So:

Code:
find . -name "*.txt" -exec awk '{CNT[FILENAME]+= gsub (/" 0"/, "&") - gsub (/"AC_STAT 0/, "&")} END {for (c in CNT) print c, CNT[c]}' {} + | awk '{TOT += $2} 1; END { print "Total", TOT}'

Or is it:

Code:
find . -name "*.txt" -exec awk '{CNT[FILENAME]+= gsub (" 0", "&") - gsub (/"AC_STAT 0/, "&")} END {for (c in CNT) print c, CNT[c]}' {} + | awk '{TOT += $2} 1; END { print "Total", TOT}'

# 13  
Old 12-04-2016
The second option. For the future: how about doing some tests and finding out by yourself?
# 14  
Old 12-04-2016
If your grep supports the P flag for Perl comparability regex then you can just make this little adjustment:

Code:
find . -name '*txt' -exec grep -PicH '(?<!"AC_STAT") 0 ' '{}' '+' | awk -F: '{ T += $2 } 1; END { print "TOTAL:" T }
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