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Shell Scripting | Return list of unique characters in files

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# 8  
Old 11-28-2016
Thanks Chubler! This expands my horizon and is easy to use. Any idea on how not having to have to input 10, 11 & 20 at all? Perhaps a range from 00 to 99? So that whatever number is at position 521-522 is returned?

---------- Post updated at 08:44 PM ---------- Previous update was at 08:35 PM ----------

Thanks Aia, you are correct, the ABC was included in the 134 or 521, I do not explain myself very well.
Last edited by clippertm; 11-28-2016 at 09:54 PM..
# 9  
Old 11-28-2016
Sorry I misinterpreted your requirements and believed you had a number of values in the range of 00 thru 99 and not all the values.

to match any two digit number I would use:

Code:
strings *.* | grep "ABCD" | cut -c 521-522 | egrep '[0-9][0-9]' | sort | uniq

This User Gave Thanks to Chubler_XL For This Post:
clippertm
# 10  
Old 11-29-2016
Quote:
Originally Posted by Chubler_XL
Sorry I misinterpreted your requirements and believed you had a number of values in the range of 00 thru 99 and not all the values.

to match any two digit number I would use:

Code:
strings *.* | grep "ABCD" | cut -c 521-522 | egrep '[0-9][0-9]' | sort | uniq

You might speed that up a little bit with:
Code:
strings *.* | awk '/ABCD/ && (s = substr($0, 521, 2)) ~ /[0-9][0-9]/ {print s}' | sort -u

But note that if you use strings on a text file, the output from strings might not be complete lines from your input files. Have you really checked the output from strings *.* is producing output with the two digits you want in positions 521 and 522?
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