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Join lines using sed or awk

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# 8  
Old 10-17-2016
Thank you, I have updated my answer to reflect this. Learning takes practice Smilie.
# 9  
Old 10-17-2016
I'm not sure that LINE1 and LINE2 are also checked.
The goal is just search PATTERN and concatenate the following 2 lines.

Either, another way in awk:
Code:
awk 'A==3{print X$0};/PATTERN/ {A=1;X=""};A>=1{++A;A%=4;X=X$0}' file

Regards.
This User Gave Thanks to disedorgue For This Post:
cmccabe
# 10  
Old 10-18-2016
Quote:
Originally Posted by greet_sed
IMO, above sed solutions will give wrong results if input has LINE3 in place of LINE1 or LINE2 for example.

Below one should work for given input patterns:
Code:
sed -ne '/PATTERN/ {N;/LINE1/N;/LINE2/s/\n//gp}' file

If the OP meant as his requirement to test for those LINES2 too, then this would not work in case PATTERN is followed by LINE2.

to test for the right order, and to ensure the pattern and lines are there, one could do something like this:
Code:
sed -n '/PATTERN/{N;N;/\n.*LINE1.*\n.*LINE2/s/\n//gp;}' file

Still a little bit better would be:
Code:
sed -n '/PATTERN/{$!N;$!N;/LINE1.*\n.*LINE2/s/\n//gp;}' file

--
Quote:
Originally Posted by RavinderSingh13
Hello Hench,

Please use code tags for commands/codes/Inputs into your posts as per forum rules, could you please try following and let me know if this helps.
Code:
awk '/PATTERN/ && A{print A;A=""} /PATTERN/ || /LINE1/ || /LINE2/{A=A?A $0:$0}'  Input_file

Output will be as follows.
Code:
PATTERNLINE1LINE2
PATTERNLINE1LINE2

Thanks,
R. Singh
Hi Ravinder, this one will not print the last pattern. You need an END section for that and you could replace /PATTERN/ || /LINE1/ || /LINE2/ with /PATTERN|LINE1|LINE2/ .

Also note that is not testing for all three lines to be present as it will still print lines if one or two lines are missing, or in the wrong order, or not adjacent.
This User Gave Thanks to Scrutinizer For This Post:
RavinderSingh13
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