String Operations


 
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# 8  
Old 04-19-2006
In ksh:

Code:
$
$ x="     12"
$ xspace=${x%%+([! ])}
$ typeset -R6 rightx=$x
$ typeset -L6 leftx=$x
$ echo number of leading blanks is ${#xspace}
number of leading blanks is 5
$ echo "rightx=<${rightx}>   leftx=<${leftx}>"
rightx=<    12>   leftx=<12    >
$

# 9  
Old 04-21-2006
a doubt

What does the below line do?
xspace=${x%%+([! ])}
It seems to be retaining only spaces. How to interpret it?

Thanks,
Ranjith
# 10  
Old 04-21-2006
You should read "man ksh", it's all in there...but briefly: ${var%%pattern} removes the largest string that matches the pattern from the end of the value of the variable. And +([! ]) is a pattern that matches non-blanks.
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