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# 1  
Old 08-31-2016
sed add special character
Hi all

I got test.test.test and need

test.test\.test *

I need the backslash before the last dot in the line

I tried

Code:
echo test.test.test | sed 's/\./\\./g'

but it gives me

test\.test\.test

Thanks
# 2  
Old 08-31-2016
Hello stinkefisch,

Following may help you in same.
Code:
echo "test.test.test" | sed 's/\(.*\.\)\(.*\)/\1\\\2 */g'

Output will be as follows.
Code:
test.test.\test *

In awk following may help you in same.
Code:
echo "test.test.test" | awk -F"." '{$NF="\\"$NF " *"} 1' OFS="."

EDIT: Adding one more solution for same now too.
Code:
cat script.ksh
A="test.test.test"
B=${A%.*}
C=${A##*.}
 echo $B".\\"$C" *"

So when we run above then following output will come.
Code:
 ./script.ksh
test.test.\test *

Thanks,
R. Singh
Last edited by RavinderSingh13; 08-31-2016 at 07:23 AM.. Reason: Added one more solution on same now.
# 3  
Old 08-31-2016
I can't figure it out ?

---------- Post updated at 05:17 AM ---------- Previous update was at 05:14 AM ----------

Quote:
Originally Posted by RavinderSingh13
Hello stinkefisch,

Following may help you in same.
Code:
echo "test.test.test" | sed 's/\(.*\.\)\(.*\)/\1.\2/g'

Output will be as follows.
Code:
test.test..test

In awk following may help you in same.
Code:
echo "test.test.test" | awk -F"." '{$NF="."$NF} 1' OFS="."

EDIT: Adding one more solution for same now too.
Code:
cat script.ksh
A="test.test.test"
B=${A%.*}
C=${A##*.}
echo $B".."$C

So when we run above then following output will come.
Code:
 ./script.ksh
test.test..test

Thanks,
R. Singh
I need test.test\.test * as output
# 4  
Old 08-31-2016
Hello stinkefisch,

Apologies for same(logic was correct and still same now) but I have put . rather than \, so changed it in above post now.

Thanks,
R. Singh
# 5  
Old 08-31-2016
Many thanks works now Smilie
# 6  
Old 08-31-2016
Small adaption to your non-working solution:
Code:
echo test.test.test | sed 's/\.[^.]*$/\\& */'
test.test\.test *

With RavinderSingh13's variable A, try:
Code:
echo "${A%.*}\\.${A##*.} *"
test.test\.test *

# 7  
Old 08-31-2016
Consider also:
Code:
echo test.test.test|sed 's/\./\\&/2
s/$/ */'

producing the output:
Code:
test.test\.test *

The 2 (or any number n) flag (specifying the nth match of the BRE in the search pattern) in the substitute command being one of the few extensions that are available in sed above and beyond the standard ed and ex editing commands capabilities.
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