Welcome to forums, hope you enjoy posting questions, sharing knowledge here. Coming to your question, I am not sure about your complete requirement but seems like you want to print from 1st line to till last line of a Input_file? If this is the case then you was close, could you please try following.
Code:
while read l
do
x=$((x+1))
printf "%04d\n" $x
done < "Input_file"
Please put your file name in place of Input_file above.
I was thinking about to use that, the problem is that originaly I had a script witch allow me to include this number in a comand to download some file.
Code:
count=0
while read p; do
echo wget -O "$2_img${count}.jpg" $p
count=$((count+1))
done <2
then, with your script I manadge to print all the line of the file,
but then it's does't seem to work to create command
I put echo to debug it but I want to make it part of a comand with wget.
I was thinking about to use that, the problem is that originaly I had a script witch allow me to include this number in a comand to download some file.
Code:
count=0
while read p; do
echo wget -O "$2_img${count}.jpg" $p
count=$((count+1))
done <2
then, with your script I manadge to print all the line of the file,
but then it's does't seem to work to create command
I put echo to debug it but I want to make it part of a comand with wget.
and get rid of the echo when you are done debugging.
PS If you tell us what operating system and shell you're using, we might also be able to suggest some shell specific shortcuts to do this. Depending on what shell and (and version of that shell) you're using, there might be shortcuts that would run slightly faster, but would be less portable.
Last edited by Don Cragun; 08-13-2016 at 01:38 PM..
Reason: Add PS.
This User Gave Thanks to Don Cragun For This Post:
Hi All ,
I am having an input file as stated below
5728 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r03_q_reg_20_/Q 011
611 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r04_q_reg_20_/Q 011
3486... (4 Replies)
Is there any program that can create 6 digit numbers with:
(DIGIT_1)+(DIGIT_2)+(DIGIT_3)+(DIGIT_4)+(DIGIT_5)+(DIGIT_6)=10
Any perl or C also can. Anyone can help me? Thank you (6 Replies)
Hi,
How I can replace last 8 ZEROS with 22991231?
19523479811841494432A2013052700000000
19523479811730333980A2013052700000000
19523479811417044397A2013052700000000
19523479811205895810C2013010120130131
A9523479811205895810A2013020120130228
19523479811205895810I2013030120130331... (9 Replies)
Hello all! I've looked all over the internet and this site and have come up a loss with an easy way to make a bash script to do what I want to do. I have a file with a naming convention as follows:
2012-01-18 string of words here 123.jpg
2012-01-18 string of words here 1234.jpg
2012-01-18... (2 Replies)
Hi Folks
Probably an easy one here but how do I get a sequence to get used as mentioned. For example in the following I want to automatically create files that have a 2 digit number at the end of their names:
m@pyhead:~$ for x in $(seq 00 10); do touch file_$x; done
m@pyhead:~$ ls file*... (2 Replies)
hi group,
How can I count total number of 5's which are continuous in the end. i.e. in the below string, the o/p should be 4
I just know to calculate total number of 5's
$ echo "95952325555" | awk -F "5" '{print NF-1}'
6 (3 Replies)
I want to check the argument in KSH. If the user type in the prompt 'find 3' it will format 3 to 003 to match the data in the text file. Same as with 10 to 010. Always begins with 0.
eg.
>find 3
Output:
003
>find 30
Output:
030 (7 Replies)
Hi there,
I am new to scripting. Can anyone help me in writing a script which will display all the digits between 1 and 5 inclusive, one digit per line. Should use a loop to do this.
Thanks in advance!! (3 Replies)
Hi All,
I am new to shell script.
I wrote a very small script that takes only digits as input-
but there is some problem in that.can you help me in debugging that.
#!/bin/ksh
echo "Digits as input"
read number
digit='eval '
if ]
then
echo "Entered number is a digit"
else
echo... (2 Replies)
Hi I'm new to this. I need to cut off the last 10 digits from a line.
I've used awk {'print $4'} filename.txt | cut -c 32-42 but this does not guarantee only the last 10 characters.
Please help. Thanks.
Sara (4 Replies)
08-13-2016
