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Top Forums Shell Programming and Scripting Script showing incorrect output
# 1  
Old 08-12-2016
Script showing incorrect output
Hello scripting geeks,

I am new to scripting and facing some issues in writing the logic of the script. Request your kind help here

Actually when i run a command i get o/p as below

o/p :

Code:
0x0000
0x0000
0x0000
0x0000
0x0000
0x0000

these are hex values i guess...now i want to read all the values and if all the values are same(i.e 0x0000) then it should print "ok" if any one or more than one values are other than 0x0000 then it should print "not ok". I have written something as below but it shows incorrect o/p

script :
Code:
for i in `db2 list tablespaces show detail | grep -i state | awk '{print $3}'`
do
     if [[ $i == 0x0000 ]]
     then
          echo "ok"
     else
          echo "not ok"
     fi
done

Can someone please help here ?


Moderator's Comments:
Mod Comment Use code tags and indention, thanks.
Last edited by zaxxon; 08-12-2016 at 03:15 AM..
# 2  
Old 08-12-2016
What is the meaning of the abbreviation "o/p"???

In your program, you loop over the whole list, and for each list element, you output either ok or not ok. There is no way that you could achieve the output you are posting, from the program you are posting.

Also, note that a

Code:
for i in `...`

is safe only if the list returned from the command is not longer than the maximum length of a command line. Whether or not this is a risk in your case, I can not say, because I don't know how large the resulting list can be.

Finally, whenever you ask about a shell issue, specify which shell you are going to use.

So, provide the code of the programm you are using, together with the output you get, and also let us know which output you expect instead.
# 3  
Old 08-12-2016
Hi rovf,

Thanks for your kind comments !!
o/p can be abbreviated as output Smilie

the list should not be more than 100 entries. my concern is, if all the values are
"0x0000" then it should display "ok" else if any one or more than one value is something other than "0x0000" then it should display "not ok". COuld you please help me in how this can be acheived ?
# 4  
Old 08-12-2016
try this..



Code:
#!/bin/bash

$(db2 list tablespaces show detail | grep -i state | awk '{print $3}') | while read i
do
     if [ $i = "0x0000" ]
     then
          echo "ok"
     else
          echo "not ok"
     fi
done

This User Gave Thanks to itkamaraj For This Post:
kulvant29
# 5  
Old 08-12-2016
Try also

Code:
db2 list tablespaces show detail | awk '/state/ && $3 != "0x0000" {RES = 1} END {print (RES?"not ":"") "OK"; exit RES}'

short version, evaluate the exit code:
Code:
db2 list tablespaces show detail | awk '/state/ && $3 != "0x0000" {exit 1}'

# 6  
Old 08-12-2016
Quote:
Originally Posted by rovf
[..]
Also, note that a

Code:
for i in `...`

is safe only if the list returned from the command is not longer than the maximum length of a command line. Whether or not this is a risk in your case, I can not say, because I don't know how large the resulting list can be.

[..]
This is not correct, there are no line length limitations to a for loop. A for loop is not a utility, it is not even a builtin utility. A for loop is part of the shell syntax, so neither the limitations of passing parameters to a subprocess apply, nor do command line limitations; for the for loop itself no command is being called and no subprocess is being started, and so neither LINE_MAX nor ARG_MAX play a role here...
Last edited by Scrutinizer; 08-12-2016 at 05:24 AM..
These 2 Users Gave Thanks to Scrutinizer For This Post:
rbatte1 wisecracker
# 7  
Old 08-12-2016
Hi Rudic,

Thank you for the code. But not displaying correct output. Like as below, if one value is other than 0x0000

Code:
>db2 list tablespaces show detail | grep -i state
 State                                = 0x0000
 State                                = 0x0000
 State                                = 0x0800 
 State                                = 0x0000
 State                                = 0x0000
 State                                = 0x0000

then also it dispalys "OK"

---------- Post updated at 03:21 PM ---------- Previous update was at 03:15 PM ----------

hi rudic,

thank you for responding,

but it shows "ok" even if any one of the entry is other than 0x0000. like below

Code:
$ db2 list tablespaces show detail | grep -i state
 State                                = 0x0000
 State                                = 0x0000
 State                                = 0x0800
 State                                = 0x0000
 State                                = 0x0000
 State                                = 0x0000
$ db2 list tablespaces show detail | awk '/state/ && $3 != "0x0000" {RES = 1} END {print (RES?"not ":"") "OK"; exit RES}'
OK


Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!
Last edited by RudiC; 08-12-2016 at 06:53 AM.. Reason: Added CODE tags.
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