Colum number where value is >0


 
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# 8  
Old 08-04-2016
With the missing if condition:
Code:
awk -F',' '{ for (i = 1; i <= NF; ++i) { if ($i > 0) { print i, $i } } }' test

Sometimes one can save the for loop by means of the RS (record separator)
Code:
awk 'BEGIN { RS="," } ($1 > 0) { print NR, $1 }' test

This User Gave Thanks to MadeInGermany For This Post:
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