I have been stuck on this for some time and invested many hours trying to find a solution. I am trying to either loop through two variables or or two arrays and not sure how to do it. I am limited to ksh only, and don't have the ability to do a foreach, or for i AND for j etc...I want to do a diff and compare version1 cmd directory to version2 cmd directory, and then iterate and compare version1 properties directory to version 2 properties directory. Can't find a similar thread. I will write a pseudo code below. I am open to other ideas.. Any help is appreciated.
Thanks for responding Rudy.
Here is an example. I know what is wrong here as the j loop iterates both, prior to going back and iterating the second i loop. Like i said i don't have the foreach or for i AND for j. I'm realizing the for loop may not be what i need here, but not sure what to do. Hope that makes sense.
Code:
#/usr/bin/ksh
old_dir="/usr/version1/cmd /usr/version1/properties"
new_dir="/usr/version2/cmd /usr/version2/properties"
for i in old_dir
do
for j in new_dir
do
print $old_dir $new_dir
done
done
Thanks Rudy. Sorry i may not have been clear, but I do not believe I'm looking for a sort here, but rather something to iterate though two variable list or two array. Here is another example:
I need one iteration for Joe Kim
then Brian Annie
then John Kate
then Mark Anna
Code:
#/usr/bin/ksh
group1="Joe Brian John Mark"
group2="Kim Annie Kate Anna"
print $group1 $group2
Thanks Rudy. Sorry i may not have been clear, but I do not believe I'm looking for a sort here, but rather something to iterate though two variable list or two array. Here is another example:
I need one iteration for Joe Kim
then Brian Annie
then John Kate
then Mark Anna
Code:
#/usr/bin/ksh
group1="Joe Brian John Mark"
group2="Kim Annie Kate Anna"
print $group1 $group2
You are still not being clear at all. There are lots of ways to iterate through two lists. The code you have shown us above obviously does not perform any iterations and just concatenates your two lists, producing output like:
Code:
Joe Brian John Mark Kim Annie Kate Anna
But if you want something that iterates through the elements of $group2 for each element of $group1, that would be something more like:
Code:
#/usr/bin/ksh
group1="Joe Brian John Mark"
group2="Kim Annie Kate Anna"
for g1 in $group1
do for g2 in $group2
do print $g1 $g2
done
done
which would give you:
Code:
Joe Kim
Joe Annie
Joe Kate
Joe Anna
Brian Kim
Brian Annie
Brian Kate
Brian Anna
John Kim
John Annie
John Kate
John Anna
Mark Kim
Mark Annie
Mark Kate
Mark Anna
But, if you just want corresponding pairs from equal length arrays, that would be something more like:
Code:
#/usr/bin/ksh
group1=(Joe "Brian Cranston" John "Brian Wilson" Mark)
group2=(Kim Annie "Sue Ann" Anna "Sue Ellen")
i=0
while [ $i -lt ${#group1[@]} ]
do printf '%s:%s\n' "${group1[i]}" "${group2[i]}"
i=$((i + 1))
done
which produces the output:
Code:
Joe:Kim
Brian Cranston:Annie
John:Sue Ann
Brian Wilson:Anna
Mark:Sue Ellen
Is one of these what you are trying to do?
You haven't said what operating system and release of that operating system you're using, so we don't know which version of the Korn shell you're using. The above was tested on Mac OS X El Capitan release 10.11.6 using /bin/ksh which is version 93u+ 2012-08-01. But I think the arrays used in these examples will also work on 1988 versions as well as 1993 versions of the Korn shell. (There are shorter, easier ways to do the last script above with a 1993 or later version of ksh.)
Last edited by Don Cragun; 07-30-2016 at 03:52 PM..
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