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UNIX Shell Scripting (Solaris) for File Checking

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Top Forums Shell Programming and Scripting UNIX Shell Scripting (Solaris) for File Checking
# 22  
Old 06-02-2016
hi don cragun,

i tried using your code but it resutls to

Code:
grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .
File "*.edi" does not contain the string "davehandsome"

may be its because of the limitations of my unix..

thank you and sorry but can you check this script of mine,
Last edited by daveaztig14; 06-08-2016 at 06:37 AM..
# 23  
Old 06-02-2016
Hello daveaztig14,

Could you please try following and let me know if this helps.
Code:
find . -type f -exec grep -H -c 'FTRORD' {} \+ | grep 0$ | cut -d':' -f1

I have checked above in BASH environment.

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
daveaztig14
# 24  
Old 06-02-2016
HI R. Sing
Last edited by daveaztig14; 06-08-2016 at 06:38 AM..
# 25  
Old 06-02-2016
Quote:
Originally Posted by daveaztig14
hi don cragun,

i tried using your code but it resutls to

Code:
grep: illegal option -- q
Usage: grep -hblcnsviw pattern file . . .
File "*.edi" does not contain the string "davehandsome"

may be its because of the limitations of my unix..

thank you and sorry but can you check this script of mine,

Code:
#!/bin/sh

cd $EDI_ROOT/MXS/inb/CHTR/FTR/9

grep -v FTRORD *

it works perfectly it goes to the directory i want and the output is the files who doesn't have the word "FTRORD" and the proof there context, please see below,

Code:
VZW997.03.26.2010:06:10:12.000:LR.hdr|VZW|997|||
VZW997.03.26.2010:06:10:12.000:LR.id||CHVZWJGC20|01||||||
VZW997.03.26.2010:06:10:12.000:LR.notify||LNIEBatch|A||
VZW997.03.26.2010:06:10:12.000:--END--
VZW997.03.26.2010:06:33:46.007:LR.hdr|VZW|997|||
VZW997.03.26.2010:06:33:46.007:LR.id||CHVZWJGC20|01||||||
VZW997.03.26.2010:06:33:46.007:LR.notify||LNIEBatch|A||
VZW997.03.26.2010:06:33:46.007:--END--
VZW997.03.26.2010:06:37:47.004:LR.hdr|VZW|997|||
VZW997.03.26.2010:06:37:47.004:LR.id||CHFTRJGC21|01||||||
VZW997.03.26.2010:06:37:47.004:LR.notify||LNIEBatch|A||
VZW997.03.26.2010:06:37:47.004:--END--
VZW997.03.26.2010:06:54:36.003:LR.hdr|VZW|997|||
VZW997.03.26.2010:06:54:36.003:LR.id||CHFTRJGC22|01||||||
VZW997.03.26.2010:06:54:36.003:LR.notify||LNIEBatch|A||
VZW997.03.26.2010:06:54:36.003:--END--

but can you help me so that the output (resutls) will only display its filename without its context?
for exapmple.. it will only result to..

Code:
VZW997.03.26.2010:06:10:12.000

thank you
What you have shown us is that there are four lines in each of the files:
Code:
VZW997.03.26.2010:06:10:12.000
VZW997.03.26.2010:06:33:46.007
VZW997.03.26.2010:06:37:47.004
VZW997.03.26.2010:06:54:36.003

that do not contain the string FTRORD. There is no indication that there is not another line in one or more of these files does contain that string.

Try using my script again, changing grep to /usr/xpg4/bin/grep.
This User Gave Thanks to Don Cragun For This Post:
daveaztig14
# 26  
Old 06-02-2016
hi don,
Last edited by daveaztig14; 06-08-2016 at 06:38 AM..
# 27  
Old 06-02-2016
Don, grep -q ... is not portable, and if ! does not work in a Bourne shell.
Instead one needs grep ... >/dev/null,
and one of the following workarounds
Code:
grep ...
if [ $? -ne 0 ]
then
  echo "not matched"
fi

or
Code:
if grep ...
then
  :
else
  echo "not matched"
fi

or
Code:
grep ... || {
  echo "not matched"
}

The following is a modification of my post #7, and greps the words in the file data.
Code:
basedir=/home
log=$basedir/dummyevents.log

for word in banana apple orange
do
  dir=$basedir/$word
  badfile=0
  
  for fname in $dir/*
  do
    if [ -f "$fname" ]
    then
      grep -w "$word" "$fname" >/dev/null
      if [ $? -ne 0 ]
      then
        echo "No '$word' in '$fname'"
        # We redirect the standard output of the whole loop
        badfile=1
      end
    fi
  done >> $log
  
  if [ $badfile -eq 1 ]
  then
    echo "Invalid file in $dir, see $log"
  fi
done

This User Gave Thanks to MadeInGermany For This Post:
daveaztig14
# 28  
Old 06-02-2016
Quote:
Originally Posted by daveaztig14
thank you and sorry but can you check this script of mine,
Code:
#!/bin/sh
..

You stated twice you were using ksh but the sample script posted here is using the legacy bourne shell /bin/sh which you should never use.

You'd rather start your scripts with one of:

Code:
#!/bin/ksh

or
Code:
#!/usr/xpg4/bin/sh

This User Gave Thanks to jlliagre For This Post:
daveaztig14
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