How to get front and back parameter of each characters?

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05-26-2016

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How to get front and back parameter of each characters?

I have list of words file. I trying to get a front and back parameter of each characters of words.

Code:

hello
....
....

Here is what I have done:

Code:

awk '{  word=$1; len=length(word); tlen=2*len-1;
        for (i=1; i<len; i++) a[i]="#";
        for (j=1; j<=len; j++) a[i+j-1]=substr(word,j,1);
        for (r=1; r<=len; r++)
            { for(i=1; i<=tlen; i++) printf "%s ", a[(i+r-2)%tlen+1];
              print " "
            }
        print " "
}' $1

Code:

# # # # h e l l o
# # # h e l l o #
# # h e l l o # #
# h e l l o # # #
h e l l o # # # #

But what I have expected to is

Code:

# # h e l  // null value replace by "#"
# h e l l
h e l l o
e l l o #
l l o # #

How to get 2 parameter front and back of each characters?

paranrat

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05-26-2016

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Not clear. What is "2 parameter front and back"?

RudiC

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05-26-2016

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Question is somewhat not clear.
just let us know..
what is expected and what you are getting. may be then we can help you.

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05-26-2016

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In this case the word is "hello"

Code:

                        h
                        e
h e l l o   - - ->      l 
                        l
                        o

focus on "h" ; before character h is null and assign with '#". After character h are "e" and "l".
focus on "e" ; before character e is "h". After character e are "l" and "l".
focus on "l" ; before character l are "h" and "e". After character l are "l" and "o".
focus on "l" ; before character l are "e" and "l". After character l is "o".
focus on "o" ; before character o are "l" and "l". After character o is null and assign with '#".

I would like to get 2 characters before and after of that focused on. I expect to get like below:

Code:

# # h e l  // 2 characters before h are "#" and "#". 2 characters after h are "e" and "l"
# h e l l  // 2 characters before e are "#" and "h". 2 characters after e are "l" and "l"
h e l l o  // 2 characters before l are "h" and "e". 2 characters after l are "l" and "o" 
e l l o #  // 2 characters before l are "e" and "l". 2 characters after l are "o" and "#"
l l o # #  // 2 characters before o are "l" and "l". 2 characters after o are "#" and "#"

paranrat

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05-26-2016

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What if you got an even character count?

RudiC

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05-26-2016

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Quote:

Originally Posted by paranrat

In this case the word is "hello"

Code:

                        h
                        e
h e l l o   - - ->      l 
                        l
                        o

focus on "h" ; before character h is null and assign with '#". After character h are "e" and "l".
focus on "e" ; before character e is "h". After character e are "l" and "l".
focus on "l" ; before character l are "h" and "e". After character l are "l" and "o".
focus on "l" ; before character l are "e" and "l". After character l is "o".
focus on "o" ; before character o are "l" and "l". After character o is null and assign with '#".

I would like to get 2 characters before and after of that focused on. I expect to get like below:

Code:

# # h e l  // 2 characters before h are "#" and "#". 2 characters after h are "e" and "l"
# h e l l  // 2 characters before e are "#" and "h". 2 characters after e are "l" and "l"
h e l l o  // 2 characters before l are "h" and "e". 2 characters after l are "l" and "o" 
e l l o #  // 2 characters before l are "e" and "l". 2 characters after l are "o" and "#"
l l o # #  // 2 characters before o are "l" and "l". 2 characters after o are "#" and "#"

Hello paranrat,

Could you please try following and let me know if this helps.

Code:

echo "h e l l o" | awk '{num=split($0, A," ");for(i=1;i<=num;i++){if(i==1){print "# #" OFS A[i] OFS A[i+1] OFS A[i+2]} else if(i==num){print A[i-2] OFS A[i-1] OFS A[i] OFS "# #"} else {Q=A[i-2] OFS A[i-1] OFS A[i] OFS A[i+1] OFS A[i+2];sub(/^[[:space:]]+/,"# ",Q);sub(/[[:space:]]+$/," #",Q);print Q}}}'

Output will be as follows.

Code:

# # h e l
# h e l l
h e l l o
e l l o #
l l o # #

Thanks,
R. Singh

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05-26-2016

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How about

Code:

awk '
        {L = length * 2
         M = int (L / 4)
         X = sprintf ("%*sY%*s", M, "", M, "")
         gsub (/ /, "#", X)
         sub  (/Y/, $1, X)
         gsub (/./, "& ", X)
         for (i=1; i<=L; i+=2) print substr (X, i, L-1)
        }
' file

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