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Search comppare replace (substr/lppad)

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# 8  
Old 05-15-2016
Is it possible you searched for 8 chars to be replaced by a 4 char zero padded string? Try
Code:
awk ' 
        {split (POS, P, "-")
         P[2]++
         LEN = P[2] - P[1]
         printf "%s%0*d%s\n", substr($0, 1, P[1]-1), LEN, substr($0, P[1], LEN), substr ($0, P[2])
        }
' POS="45-55" file
XXXXXXX XXXXX                 MM11111    ZM    0         000000000000000000000OREGON XXXXXXX HXN  001111  01010  -->Original
XXXXXXX XXXXX                 MM11111    ZM 00000000000  000000000000000000000OREGON XXXXXXX HXN  001111  01010  --> After

This User Gave Thanks to RudiC For This Post:
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# 9  
Old 05-16-2016
Thanks Rudic. Your code is working fine. I did some mistake in the positional notation.

Thank You Don for jumping in and assisting.

Aia - I will definitely try all the codes you have mentioned.

Many thanks to everyone for your kind help.
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