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Conditional OR in shell

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# 8  
Old 04-25-2016
Quote:
Originally Posted by Scrutinizer
This could be simplified further still:
Code:
if ls -A "$apache_log_dir"/*.log "$jboss_log_dir"/*.log 1>/dev/null 2>&1; then

No, it can't. This script needs to continue if there is a matching file in either directory.
Code:
ls -A "$apache_log_dir"/*.log "$jboss_log_dir"/*.log 1>/dev/null 2>&1

will give a non-zero exit status if the match in either directory fails.
Code:
[[ $(ls -A $apache_log_dir/*.log $jboss_log_dir/*.log 2>/dev/null) ]]

will give a non-zero exit status only if neither directory contains a matching file.
This User Gave Thanks to Don Cragun For This Post:
Scrutinizer
# 9  
Old 04-25-2016
SmilieYes you are 100% right .. It is testing a different thing and I never realized ls would return 1 if one of files is not present even if all the other ones are..


---
full shell solution (without line length limitations):
Code:
file_exists() {
  for _i do
    [ -e "$_i" ] && break
  done
}

if exists "$apache_log_dir"/*.log23 "$jboss_log_dir"/*.log

Last edited by Scrutinizer; 04-25-2016 at 08:40 AM..
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